题目描述
对于一元多项式 p(x)=p0+p1x+p2x2+ … +pnxn ,每个项都有系数和指数两部分,例如p2x2的系数为p2,指数为2。
编程实现两个多项式的相加。
例如5+x+2x2+3x3,-5-x+6x2+4x4,两者相加结果:8x2+3x3+4x4
其中系数5和-5都是x的0次方的系数,相加后为0,所以不显示。x的1次方同理不显示。
可用顺序表或单链表实现。
输入
第1行:输入t表示有t组测试数据
第2行:输入n表示有第1组的第1个多项式包含n个项
第3行:输入第一项的系数和指数,以此类推输入n行
接着输入m表示第1组的第2个多项式包含m项
同理输入第2个多项式的m个项的系数和指数
参考上面输入第2组数据,以此类推输入t组
假设所有数据都是整数
输出
对于每1组数据,先用两行输出两个原来的多项式,再用一行输出运算结果,不必考虑结果全为0的情况
输出格式参考样本数据,格式要求包括:
1.如果指数或系数是负数,用小括号括起来。
2.如果系数为0,则该项不用输出。
3.如果指数不为0,则用符号^表示,例如x的3次方,表示为x^3。
4.多项式的每个项之间用符号+连接,每个+两边加1个空格隔开。
样例查看模式
正常显示查看格式
输入样例1 <-复制
输出样例1
语言: 编译选项
主题:
!!!!这是原版,但是不知道什么原因无法通过
#include<iostream>
using namespace std;
#define ok 0
#define error -1
class ListNode
{
public:
int data1;
int data2;
ListNode* next;
ListNode()
{
next = NULL;
}
};
class LinkList
{
public:
ListNode* head;
int len;
LinkList();
~LinkList();
ListNode* LL_index(int i);
int LL_insert(int i, int item1, int item2);
int LL_del(int i);
int getlen();
int assign(LinkList& f, string n);
int fanhui(LinkList& f, int number);
void display_free();
void display_used();
void add(LinkList& l);
void display();
};
LinkList::LinkList()
{
head = new ListNode();
len = 0;
}
LinkList::~LinkList()
{
ListNode* p, * q;
p = head;
while (p != NULL)
{
q = p;
p = p->next;
delete q;
}
len = 0;
head = NULL;
}
ListNode* LinkList::LL_index(int i)
{
if (i < 0 || i > len)
{
return NULL;
}
ListNode* p = head;
for (int j = 0; j < i; j++)
{
p = p->next;
}
return p;
}
int LinkList::LL_insert(int i, int item1,int item2)
{
if (i <= 0 || i > len + 1)
{
return error;
}
else
{
ListNode* p = LL_index(i - 1);
ListNode* s = new ListNode();
s->data1 = item1;
s->data2 = item2;
s->next = p->next;
p->next = s;
len += 1;
return ok;
}
}
int LinkList::LL_del(int i)
{
if (i <= 0 || i > len)
{
return error;
}
else
{
ListNode* p = LL_index(i - 1);
ListNode* s = p->next;
p->next = s->next->next;
delete s;
len -= 1;
return ok;
}
}
int LinkList::getlen()
{
return len;
}
void LinkList::add(LinkList &q)
{
ListNode* pre = head;
ListNode* s = pre->next;
ListNode* r = q.head->next;
while (s != NULL && r != NULL)
{
if (s->data2 < r->data2)
{
s = s->next;
pre = pre->next;
}
else if (s->data2 == r->data2)
{
s->data1 += r->data1;
s = s->next;
pre = pre->next;
r = r->next;
q.len--;
}
else
{
ListNode* m = new ListNode();
m->data1 = r->data1;
m->data2 = r->data2;
m->next = s;
pre->next = m;
r = r->next;
pre = pre->next;
q.len--;
}
}
//如果r有剩余
if (r)
{
pre->next = r;
len += q.len;
}
display();
}
void LinkList::display()
{
int i;
ListNode* p = head->next;
for (i = 0; i < len; i++)
{
if (p->data1 == 0)
{
p = p->next;
continue;
}
else if (p->data2 == 0)
{
if (p->data1 < 0)
cout << "(" << p->data1 << ")";
else
cout << p->data1;
p = p->next;
}
else
{
if (p->data1 < 0)
cout << "(" << p->data1 << ")x^";
else
cout << p->data1 << "x^";
if (p->data2 < 0)
cout << "(" << p->data2 << ")";
else
cout << p->data2;
p = p->next;
}
if (i != len - 1)
cout << " + ";
}
cout << endl;
}
int main()
{
int t;
cin >> t;
while (t--)
{
int n;
cin >> n;
int number, zhishu;
LinkList p;
LinkList q;
ListNode* l = p.head;
for (int i = 0; i < n; i++)
{
cin >> number >> zhishu;
ListNode* n2 = new ListNode();
n2->data1 = number;
n2->data2 = zhishu;
l->next = n2;
n2->next = NULL;
l = n2;
}
p.len = n;
p.display();
cin >> n;
ListNode* l1 = q.head;
for (int i = 0; i < n; i++)
{
cin >> number >> zhishu;
ListNode *n1 = new ListNode();
n1->data1 = number;
n1->data2 = zhishu;
l1->next = n1;
n1->next = NULL;
l1 = n1;
}
q.len = n;
q.display();
p.add(q);
}
cout << endl;
return 0;
}
!!!这是网上合法的版本
#include <iostream>
using namespace std;
class ListNode
{
public:
int data1, data2;
ListNode *next;
ListNode()
{
next = NULL;
}
};
class linklist
{
public:
ListNode *head;
int len;
linklist()
{
head = new ListNode;
len = 0;
}
~linklist()
{
ListNode *p, *q;
p = head;
while(p)
{
q = p;
p = p->next;
delete q;
}
len = 0;
head = NULL;
}
void createlist(int n)
{
int i;
ListNode *q = head;
int d1, d2;
for(i = 0; i < n; i++)
{
cin >> d1 >> d2;
ListNode *p = new ListNode;
p->data1 = d1;
p->data2 = d2;
q->next = p;
p->next = NULL;
q = p;
}
len = n;
}
void display()
{
int i;
ListNode *p = head->next;
for(i = 0; i < len; i++)
{
if(p->data1 == 0)
{
p = p->next;
continue;
}
else if(p->data2 == 0)
{
if(p->data1 < 0)
cout << "(" << p->data1 << ")";
else
cout << p->data1;
p = p->next;
}
else
{
if(p->data1 < 0)
cout << "(" << p->data1 << ")x^";
else
cout << p->data1 << "x^";
if(p->data2 < 0)
cout << "(" << p->data2 << ")";
else
cout << p->data2;
p = p->next;
}
if(i != len-1)
cout << " + ";
}
cout << endl;
}
void add(linklist *q)
{
ListNode *pre = head;
ListNode *s = pre->next;
ListNode *r = q->head->next;
while(s != NULL && r != NULL)
{
if(s->data2 < r->data2)
{
s = s->next;
pre = pre->next;
}
else if(s->data2 == r->data2)
{
s->data1 = s->data1+r->data1;
s = s->next;
pre = pre->next;
r = r->next;
q->len--;
}
else
{
ListNode *m = new ListNode;
m->data1 = r->data1;
m->data2 = r->data2;
m->next = s;
pre->next = m;
r = r->next;
pre = pre->next;
//len++;
q->len--;
}
}
if(r)
{
pre->next = r;
len = len+q->len;
}
}
ListNode *index(int i)
{
int k;
ListNode *p = head;
if(i != 0)
{
for(k = 1; k < i; k++)
{
p = p->next;
}
return p->next;
}
else
{
return head;
}
}
};
int main()
{
int T, n, m;
cin >> T;
while(T--)
{
linklist *l1 = new linklist,*l2 = new linklist;
cin >> n;
l1->createlist(n);
cin >> m;
l2->createlist(m);
l1->display();
l2->display();
l1->add(l2);
l1->display();
delete l1, l2;
}
return 0;
}