list.c
#define _CRT_SECURE_NO_WARNIGNS
#include<stdio.h>
#include<stdbool.h>
typedef struct node_s {
int data;
struct node_s* next;
} Node;
void add_before_head(Node** plist, int data) {
// 创建结点
Node* newNode = malloc(sizeof(Node));
if (!newNode) {
printf("Error: malloc failed in add_before_head.\n");
exit(1);
}
// 初始化结点
newNode->data = data;
// 头插法
newNode->next = *plist;
*plist = newNode;
}
void display_list(Node* list) {
Node* curr = list;
while (curr != NULL) {
printf("%d ", curr->data);
curr = curr->next;
}
printf("\n");
}
Node* search_list(Node* list, int val) {
Node* curr = list;
while (curr != NULL) {
if (curr->data == val) {
return curr;
}
curr = curr->next;
}
return NULL;
}
void free_list(Node* list) {
Node* curr = list;
while (curr != NULL) {
Node* next = curr->next;
free(curr);
curr = next;
}
}
int middleElement(Node* list) {
Node* curr = list;
int n = 0;
while (curr) {
n++;
curr = curr->next;
}
curr = list;
for (int i = 0; i < n / 2; i++) {
curr = curr->next;
}
return curr->data;
}
// 方式二
int middleElement2(Node* list) {
Node* slow = list;
Node* fast = list;
// fast == NULL || fast->next == NULL
while (fast != NULL && fast->next != NULL) {
slow = slow->next;
fast = fast->next->next;
}
return slow->data;
}
bool hasCircle(Node* list) {
Node* fast = list;
Node* slow = list;
do {
// 如果 fast 到达了链表的末尾
if (fast == NULL || fast->next == NULL) {
return false;
}
fast = fast->next->next;
slow = slow->next;
} while (fast != slow);
// 循环结束: fast == slow, 说明链表有环
return true;
}
Node* reverse(Node* list) {
Node* prev = NULL;
Node* curr = list;
while (curr != NULL) {
// 保留curr的后继结点
Node* next = curr->next;
// 反转当前结点
curr->next = prev;
// 更新prev和curr
prev = curr;
curr = next;
}
//循环结束: curr == NULL, prev指向反转后的第一个结点
return prev;
}
// 递归方式
Node* reverse2(Node* list) {
// 边界条件
if (list == NULL || list->next == NULL) {
return list;
}
// 递归公式
Node* result = reverse(list->next);
list->next->next = list;
list->next = NULL;
return result;
}
Node* merge_two_lists(Node* list1, Node* list2) {
Node dummynode = {0,NULL};
Node* curr1 = list1;
Node* curr2 = list2;
Node* tail = &dummynode;
while(curr1 != NULL && curr2!= NULL){
if (curr1->data < curr2->data) {
tail->next = curr1;
tail = curr1;
curr1 = curr1->next;
}
else {
tail->next = curr2;
tail = curr2;
curr2 = curr2->next;
}
}
tail->next = curr1 ? curr1 : curr2;
return dummynode.next;
}
int main() {
Node l1p3 = { 5,NULL };
Node l1p2 = { 3,&l1p3 };
Node l1p1 = { 1,&l1p2 };
Node l2p3 = { 6,NULL };
Node l2p2 = { 4,&l2p3 };
Node l2p1 = { 2,&l2p2 };
Node* new_list = merge_two_lists(&l1p1, &l2p1);
Node* curr = new_list;
display_list(curr);
return 0;
}