一、题目
要求:实现全网可达
二、拓扑图:
三、实验过程:
1、配置IP地址:
R1
g0/0/0 192.168.0.1 27
g0/0/1 192.168.0.33 27
g0/0/2 192.168.0.66 27
R2
g0/0/0 192.168.0.34 27
g0/0/1 192.168.0.97 27
R3
g0/0/0 192.168.0.129 27
g0/0/1 192.168.0.65 27
R4
g0/0/0 192.168.0.98 27
g0/0/1 192.168.0.130 27
g0/0/2 192.168.0.161 27
PC1
PC2
2、配置路由:
R1
192.168.0.96 27 192.168.0.34
192.168.0.128 27 192.168.0.65
配置负载均衡
192.168.0.160 27 192.168.0.34
192.168.0.160 27 192.168.0.65
R2
192.168.0.0 27 192.168.0.33
192.168.0.64 27 192.168.0.33
192.168.0.160 27 192.168.0.98
192.168.0.128 27 192.168.0.98
R3
192.168.0.0 27 192.168.0.66
192.168.0.32 27 192.168.0.66
192.168.0.160 27 192.168.0.130
192.168.0.96 27 192.168.0.130
R4
192.168.0.32 27 192.168.0.97
192.168.0.160 27 192.168.0.129
配置负载均衡
192.168.0.0 27 192.168.0.97
192.168.0.160 27 192.168.0.129
四、测试直连
经过测试,可实现全网可达。