删除字符串中出现最少的字符

可以用字符数组做，但是要倒来倒去，逻辑也不清晰

还是用map键值对好，逻辑也清晰，平时用得少，业务不熟啊

int main()
{
char A[100] = {};
typedef map<char, int>mm;
mm m;
scanf("%s",A);
int len = strlen(A);
//build key-value
for (int i = 0; i < len; i++)
{
mm::iterator ii = m.find(A[i]);
if (ii == m.end())
{
m[A[i]] = 1;
}
else
m[A[i]]++;
}
int min1 = len;
//find the least num
for (mm::iterator ii = m.begin(); ii != m.end(); ii++)
{
if (ii->second < min1)min1 = ii->second;


}
//print char
for (int i = 0; i < len; i++)
{
if (m[A[i]] != min1)printf("%c",A[i]);
}
printf("\n");
return 0;
}