C语言实现时间的加一天或者减一天

转换思路利用time_t类型来进行时间的换算。

 

#include <stdio.h>

#include <string.h>

#include <stdlib.h>

#include <string>

#include <time.h>

 

using std::string;

#pragma  warning(disable:4996)

int main()

{

         string _strDealDate("20120124");

         charszDate[20]= { 0 };

         intYear= 0, Month = 0, Day= 0, Hour = 0, Min= 0, Second = 0;

 

         strcpy(szDate, (char*)_strDealDate.substr(0, 4).c_str());

         printf("%s\n",szDate);

 

         //获取当前时间

         time_t curTime = time(NULL);

 

         structtm* t= localtime(&curTime);

 

         printf("%4d %02d %02d\n",

                   t->tm_year+ 1900, t->tm_mon+ 1, t->tm_mday);//获取当前的日期

         printf( "%02d %02d %02d\n",t->tm_hour,t->tm_min,t->tm_sec);  // 获取当前的时间

 

         //获取减一天后的时间

         time_t preDay = curTime- 3600 * 24;

 

         t= localtime(&preDay);

         printf("%4d %02d %02d\n",

                   t->tm_year+ 1900, t->tm_mon+ 1, t->tm_mday);//获取前一天的日期

         printf("%02d %02d %02d\n",t->tm_hour,t->tm_min,t->tm_sec);  // 获取前一天的时间

 

         //获取加一天后的时间

         time_t preDay = curTime+ 3600 * 24;

 

         t= localtime(&preDay);

         printf("%4d %02d %02d\n",

                   t->tm_year+ 1900, t->tm_mon+ 1, t->tm_mday);//获取一天后的日期

         printf("%02d %02d %02d\n",t->tm_hour,t->tm_min,t->tm_sec);  // 获取一天后的时间

 

         return0;

}

 

运行结果