HDU4492:Mystery

最新推荐文章于 2020-04-13 00:34:07 发布

键盘上的舞者

最新推荐文章于 2020-04-13 00:34:07 发布

阅读量1.1k

点赞数

CC 4.0 BY-SA版权

分类专栏：水文章标签： ACM HDU

本文链接：https://blog.youkuaiyun.com/libin56842/article/details/8896656

水专栏收录该内容

330 篇文章

订阅专栏

本文解析了一道ACM竞赛中的输入输出题目，详细介绍了如何读取特定格式的数据并根据给定规则输出相应的字符串。通过示例输入输出展示了算法的具体实现过程。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

Input

The first line of input contains a single integer P, (1 <= P <= 1000), which is the number of data sets that follow. Each data set consists of several lines. Each data set should be processed identically and independently.

The first line of each data set contains an integer D which is the data set number. The second line contains no more than the 93 distinct printable ASCII characters. The third line contains an integer, N (1 <= N <=512 ), which is the number of integers on the next (fourth) line of the dataset. Each integer on the fourth line is in the range -X to X where X is the number of characters on the second line minus 1.

Output

For each data set there is one correct line of output. It contains the data set number (D) followed by a single space, followed by a string of length N made of the characters on the second line of the input data set.

Sample Input

4
1
MAC
3
1 1 1
2
IW2C0NP3OS 1RLDFA
22
0  3  3  -3  7  -8  2  7  -4  3  8  7  4  1  1  -4  5  2  5  -6  -3  -4
3
G.IETSNPRBU
17
2  4  5  -6  -1  -3  -2  -4  -4  1  -1  5  -3  4  1  -2  4
4
PIBN MRDSYEO
16
-4  4  -1  4  5  3  -5  4  -3  -3  -2  -5  -5  -3  1  3

Sample Output

1 ACM
2 ICPC 2013 WORLD FINALS
3 IN ST. PETERSBURG
4 SPONSORED BY IBM

累加确定位置，然后输出就是了

#include <stdio.h>
#include <string.h>

int main()
{
    int n;
    scanf("%d",&n);
    while(n--)
    {
        int t;
        scanf("%d%*c",&t);
        printf("%d ",t);
        char str[10000];
        gets(str);
        int i,len = strlen(str);
        char c;
        int tem = 0,k,a;
        scanf("%d",&k);
        for(i = 0; i<k; i++)
        {
            scanf("%d",&a);
            tem+=a;
            tem = (tem+len)%len;
            printf("%c",str[tem]);

        }
        puts("");
    }
    return 0;
}