看到这些代码,我自叹不如!!!

这篇博客探讨了JavaScript错误处理的最佳实践,展示了一段可能世界上最难的Hello World代码,涉及复杂字符串操作。还分享了一段潜在危险的命令行代码,并揭示了一个隐晦的表白代码,使用ASCII字母构建单词。最后,博主警告读者不要轻易尝试执行某些代码,特别是涉及删除操作的命令。

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1、JavaScript 错误处理的正确姿势

这个代码毫无破绽啊!!!

try {
    something
} catch (e) {
    window.location.href = "https://stackoverflow.com/search?q=[js]+" +
          e.message;
}

3360bed6157e1d0865f7731589d355bf.png

2、可能是世界上最难的 hello world 了?

这个要怎么敲出来!!!

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e6eada61630227481b5b703db3ef0486.png

3、发这个代码,没人知道你骂他

(!(~+[])+{})[--[~+""][+[]]*[~+[]] + ~~!+[]]+({}+[])[[~!+[]]*~+[]]

8350895c76d58fae9e5a4860c4a77cb7.png

需要的可以保存图片:

46df3b29688f562d0f7653e33a90e3a1.png

4、委婉的表白

猜猜输出是什么?

import string
l = string.ascii_letters
s = []
s.append(l[34])
s.append(l[11])
s.append(l[14])
s.append(l[21])
s.append(l[4])
s.append(l[24])
s.append(l[14])
s.append(l[20]) 
s.insert(1, " ")
s.insert(6, " ") 
string = "".join(s)
print(string)

842a3dad8ec2e63debc44084cbca04f1.png

5、针对不给钱的客户

009ae3d7369faab89c3c16711ce9a15e.png

6、代码也写出心型

#include    <iostream>
  int main() {  int A=43,B=A/2,
 C=B/2,x,y,i=B,j=-C;for(y=0;y<B;
j=(++y)-(C+C/8)) {for(x=0; x<A;i=
 abs((++x)-B)+j){std::cout<<((i*i
  /2+j*j<(C*C*2)/3)?"*":" ");}
      std::cout<<std::endl
           ;}return 
              0;}

8bc8c528e839bca37721aba70074820b.png

7、这个不要轻易尝试

执行这个有生命危险!!!

sudo rm -rf /*

596dc4f2b33f9eb54035fb83b93107b6.png

8、最牛逼的还是价值一个亿的AI核心代码!

while True:    
    print(input('').replace('吗','').replace('?','!'))

0c88eb2ac616b0176765af1523ac04da.png

测试下效果:

70d0227ac680b0a9404e8b18eebd0a64.png

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