How many days?
Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 5145 Accepted Submission(s): 3056
Problem Description
8600的手机每天消费1元,每消费K元就可以获赠1元,一开始8600有M元,问最多可以用多少天?
Input
输入包括多个测试实例.每个测试实例包括2个整数M, k,(2 <= k <= M <= 1000).M = 0, k = 0代表输入结束.
Output
对于每个测试实例输出一个整数,表示M元可以用的天数。
Sample Input
2 2 4 3 0 0
Sample Output
3 5
Author
8600
Source
Recommend
#include<stdio.h>
int main()
{
int m,s,k,i,p;
while(scanf("%d%d",&m,&k)!=EOF&&(m!=0||k!=0))
{
s=m;
while(m>=k)
{
s+=m/k;
m=m%k+m/k;
}
printf("%d\n",s);
}
return 0;
}