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给出下三角矩阵 求单源最短路中的最长路

求下最短路就好,考读题。。

//求单源最短路中的最长路
#include <cstdio>
#include <algorithm>
#include <queue>
#include <cstring>
#include <cmath>
#include <cstdlib>
using namespace std;
typedef pair<int,int> PII;
const int MAXN=107;
const int MAXM=MAXN*MAXN/2;
const int INF=0x3f3f3f3f;
int head[MAXN],to[MAXM<<1],ne[MAXM<<1],n,m,w,ecnt,T;
int dist[MAXN],wt[MAXM<<1];
void init()
{
    ecnt=0;
    memset(head,0,sizeof(head));
}
void addedge(int a,int b,int c)
{
    ne[++ecnt]=head[a];
    head[a]=ecnt;
    to[ecnt]=b;
    wt[ecnt]=c;
}
queue<int> q;
int inq[MAXN],vis[MAXN];
int spfa(int s)
{
    while(!q.empty())
        q.pop();
    for(int i=1;i<=n;i++)
        dist[i]=INF,inq[i]=0,vis[i]=0;
    dist[s]=0;
    inq[s]=1;
    q.push(s);
    int ta;
    while(!q.empty())
    {
        int fr=q.front();
        q.pop();
        inq[fr]=0;
        for(int i=head[fr];i;i=ne[i])
        {
            int v=to[i];
            ta=dist[fr]+wt[i];
            if(dist[v]>ta)
            {
                dist[v]=ta;
                if(inq[v])continue;
                if(++vis[v]>=n)//存在负环
                    return -1;
                inq[v]=1;
                q.push(v);
            }
        }
    }
    return 1;
}
int main()
{
    int ta;
    char tb[10];
    scanf("%d",&n);
    init();
    for(int i=1;i<=n;i++)
    {
        for(int j=1;j<i;j++)
        {
            scanf("%s",tb);
            if(tb[0]=='x')
                continue;
            ta=atoi(tb);
            addedge(i,j,ta);
            addedge(j,i,ta);
        }
    }
    spfa(1);
    int maxl=0;
    for(int i=1;i<=n;i++)
        maxl=max(maxl,dist[i]);
    printf("%d\n",maxl);
    return 0;
}
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Poj1502 MPI Maelstrom (最短路)

题意: N个处理器要进行信息传递,处理器i传递信息给自己不需要时间,处理器i与处理器j之间相互传递信息的时间是一样的,不同处理器之间传递信息所需要的时间由一个矩阵的下三角给出。若矩阵对应位置为x,则说明相应的两个处理器之间无法传递信息。求从第一个处理器传递信息到其他所有处理器最少需要多少时间。 题意复制自:https://blog.youkuaiyun.com/alongela/article/details...

CY05627的博客 228

poj1502 MPI Maelstrom(单源最短路)

题意:表面乍一看output是输出最小值,但仔细研究可以发现,这个最小值是从点1到所有点所花时间的最小值,其实是访问这些节点中的最大值,因为只有访问了最长时间的那个点才算访问了所有点。所以求最短路之后求最大值。 #include <iostream> #include <cstring> #include <cstdio> using namespa...

weixin_30294021的博客 113

最短路dijkstra—MPI Maelstrom(POJ - 1502)

题目链接:>_> 题目:MPI Maelstrom BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem....

Darge. 251

POJ 1502 - MPI Maelstrom(单源最短路)

MPI Maelstrom Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 8783 Accepted: 5403 DescriptionBIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Ody

Snakeflute的博客 381

POJ 1502 - MPI Maelstrom(单源最短路)

MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 4531   Accepted: 2744 Description BIT has recently taken delivery of their new supercomputer,

coco430的专栏 732
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