探讨了在限定范围内，不同基数a和指数b的幂运算结果中唯一数值的数量。通过对2到100之间的整数进行幂运算并去除重复项的方法，统计了不重复的幂运算结果数量。
Consider all integer combinations of ab for 2 ≤ a ≤ 5 and 2 ≤ b ≤ 5:
2^2=4, 2^3=8, 2^4=16, 2^5=32
3^2=9, 3^3=27, 3^4=81, 3^5=243
4^2=16, 4^3=64, 4^4=256, 4^5=1024
5^2=25, 5^3=125, 5^4=625, 5^5=3125
If they are then placed in numerical order, with any repeats removed, we get the following sequence of 15 distinct terms:
4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125
How many distinct terms are in the sequence generated by a^b for 2 ≤ a ≤ 100 and 2 ≤ b ≤ 100?
最简单的办法，使用集合，将所有结果都添加到集合里，返回集合长度即可。
2，4，16；3，9，81；5，25；6，36；7，49；8，64；这些数中间有很多重复的。比如2和4之间只有100个不重复的结果。
2^2=4, 2^3=8, 2^4=16, 2^5=32
3^2=9, 3^3=27, 3^4=81, 3^5=243
4^2=16, 4^3=64, 4^4=256, 4^5=1024
5^2=25, 5^3=125, 5^4=625, 5^5=3125
If they are then placed in numerical order, with any repeats removed, we get the following sequence of 15 distinct terms:
4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125
How many distinct terms are in the sequence generated by a^b for 2 ≤ a ≤ 100 and 2 ≤ b ≤ 100?
最简单的办法，使用集合，将所有结果都添加到集合里，返回集合长度即可。
2，4，16；3，9，81；5，25；6，36；7，49；8，64；这些数中间有很多重复的。比如2和4之间只有100个不重复的结果。
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