hdu 3927 Math Geek 反幻方构造

Problem Description

Sheldon's board has been changed! Someone drew a N * N grid on his board. Although he has no idea who's the bad guy, but as a math geek, he decide to play a game on it. He will fill in the grids with integer 1 to N*N. And the sum of each row, each column and each diagonal are distinct (2N+2 distinct integers in total).

 

 

Input

The first line contains a single positive integer T( T <= 200 ), indicates the number of test cases.
For each test case: an integer N (3 <= N <= 200).

 

 

Output

For each test case: output the case number as shown and an N * N matrix.
The output must contains N+1 lines, or you maybe get wrong answer because of special judge.
The numbers in each line must be separated by a blankspace or a tab. leading and trailing blankspace will be ignored.

 

 

Sample Input

2
3
4

 

 

Sample Output

Case #1:
7 5 2
1 4 8
3 6 9
Case #2:
2 8 15 1
5 12 10 16
6 9 4 14
3 7 11 13

 

 

 //

 

#include <cstdio>
int main()
{
    int T;
    int cas = 1;
    scanf("%d", &T);
    while(T--)
    {
        int n;
        scanf("%d", &n);
        printf("Case #%d:\n",cas++);
        for(int i = 1; i <= n; i++)
        {
            for(int j = 1; j < n; j++)
            {
                printf("%d ", (i-1)*(n-1)+j);
            }
            printf("%d\n", n*(n-1)+i);
        }
    }
    return 0;
}