PAT A1058. A+B in Hogwarts (20)

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本文介绍了一个基于哈利波特魔法世界货币系统的计算程序。该程序能够接收两种标准形式的魔法货币（Galleon.Sickle.Knut），并计算它们的总和，最终以同样的格式输出结果。

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 10⁷], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28

#include <cstdio>
#include <algorithm>
#include <cmath>
#include <cstring>
#define Max 110
using namespace std;
struct Money
{
	int s,g,k;
}a,b,c;
int main()
{
	scanf("%d.%d.%d%d.%d.%d",&a.s,&a.g,&a.k,&b.s,&b.g,&b.k);
	c.g=c.k=c.s=0;
	c.k=c.k+a.k+b.k;
	c.g+=(c.k/29);
	c.k=c.k%29;
	c.g=c.g+a.g+b.g;
	c.s=c.s+(c.g/17);
	c.g=c.g%17;
	c.s=c.s+a.s+b.s;
	printf("%d.%d.%d\n",c.s,c.g,c.k);
	system("pause");
	return 0;
}