假设两个ViewController之间已经建立了Segue
A:TableViewController的子类 B:viewController A --> B 传送数据类Player的对象player
1.设置Segue的identifier
2.在B.h里添加
@property(nonatomic,strong) Player *player;
在B.m里添加
@synthesize player;
3.在A.m里重写UIViewController 的以下方法
-(void) prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender{
UIViewController *destination = segue.destinationViewController;
if ([destination respondsToSelector:@selector(setPlayer:)]){//判断目标是否存在setPlayer方法
[destination setValue:selectedPlayer forKey:@"player"];
}
}
4.在A.m里重写
- (NSIndexPath *)tableView:(UITableView *)tableView willSelectRowAtIndexPath:(NSIndexPath *)indexPath{
selectedPlayer = [players objectAtIndex:indexPath.row];
return indexPath;
}
说明:之所以不重写
- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath;
是因为执行顺序,不然会取不到值:
willSelectRowAtIndexPath --> prepareForSegue --> didSelectRowAtIndexPath
5.OK,传送成功!在B里已经可以用player对象了。