点到矩形的距离

最新推荐文章于 2023-09-13 14:05:45 发布

iteye_15461

最新推荐文章于 2023-09-13 14:05:45 发布

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分类专栏： android 文章标签：人工智能 python swift

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float closestX, closestY;

    if(point.x >= x1 && point.x <= x2 && point.y >= y1 && point.y <= y2)
    {
         float bestDistance = point.y - y1;
         bestDistance = Math.min(distance, y2 - point.y);
         bestDistance = Math.min(distance, point.x - x1);
         bestDistance = Math.min(distance, x2 - point.x);

         return bestDistance;
    }

    if (point.x < x1) {
        closestX = x1;
    } else if (point.x > x2) {
        closestX = x2;
    } else {
        closestX = point.x;
    }

    if (point.y < x1) {
        closestY = y1;
    } else if (point.y > y2) {
        closestY = y2;
    } else {
        closestY = point.y;
    }

    float vectorY = point.x - closestX;
    float vectorY = point.Y - closestY;

    float distance = sqrtf((vectorX * vectorX) + (vectorY * vectorY));