HDU求数列的和
求数列的和
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 132743 Accepted Submission(s): 78672
Problem Description
数列的定义如下:
数列的第一项为n,以后各项为前一项的平方根,求数列的前m项的和。
Input
输入数据有多组,每组占一行,由两个整数n(n<10000)和m(m<1000)组成,n和m的含义如前所述。
Output
对于每组输入数据,输出该数列的和,每个测试实例占一行,要求精度保留2位小数。
Sample Input
81 4
2 2
Sample Output
94.73
3.41
#include <stdio.h>
#include <math.h>
int main() {
int n,m;
double x = 0;
double z = 0;
int y;
while(scanf("%d%d",&n,&m) != EOF){
x = x + n;
z = n;
for(y = 0; y < m-1; y++){
x = x + sqrt(z);
z = sqrt(z);
}
printf("%.2lf\n",x);
x = 0;
}
return -1;
}