|
Problem Description
Your task is to calculate the sum of some integers.
|
|
Input
Input contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line.
|
|
Output
For each group of input integers you should output their sum in one line, and you must note that there is a blank line between outputs.
|
|
Sample Input
3 4 1 2 3 4 5 1 2 3 4 5 3 1 2 3 |
|
Sample Output
10 15 6 |
#include <stdio.h>
int main(void)
{
int n, m, a, sum, i, j;
scanf("%d", &n);
for(i = 0; i < n; i ++)
{
scanf("%d", &m);
sum = 0;
for(j = 0; j < m; j ++)
{
scanf("%d", &a);
sum = sum + a;
}
printf("%d\n", sum);
if(i != n - 1)
printf("\n");
}
return 0;
}
本文介绍了一个计算整数序列和的问题,通过输入一组整数并输出它们的总和,展示了基本的编程逻辑和算法应用。
1224

被折叠的 条评论
为什么被折叠?



