Problem Description
Your task is to Calculate the sum of some integers.
Input
Input contains multiple test cases. Each test case contains a integer N, and then N integers follow in the same line. A test case starting with 0 terminates the input and this test case is not to be processed.
Output
For each group of input integers you should output their sum in one line, and with one line of output for each line in input.
Example Input
4 1 2 3 4 5 1 2 3 4 5 0
Example Output
1015
答案:
#include<iostream> //#include<stdio.h> #include<iomanip> using namespace std; int main() { //int n, x, sum;//C语言版本 //while (scanf("%d", &n) && n != 0) //{ // sum = 0; // while (n--) // { // scanf("%d", &x); // sum += x; // } // cout<< sum <<endl; //} int n, x, sum;//C++版本。 while (cin >> n && n != 0)//可以看出这种输入格式时,Cin也可以做到。 { sum = 0; while (n--) { cin >> x; sum += x; } cout<< sum <<endl; } return 0; }
本文介绍了一个使用C++编写的简单程序,该程序能够读取多组整数并计算每组整数的总和。文章提供了完整的源代码示例,并展示了如何通过标准输入接收整数并输出计算结果。
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