按键加减

最新推荐文章于 2023-07-19 20:03:43 发布

huangchun96

最新推荐文章于 2023-07-19 20:03:43 发布

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CC 4.0 BY-SA版权

本文链接：https://blog.youkuaiyun.com/huangchun96/article/details/54649529

本文介绍了一种使用51单片机实现LED数码管动态显示的方法，并通过两个按键实现数字的加减控制。代码中包含了定时器初始化、延时函数及主程序流程，展示了如何设置数码管的段码和位码，以及如何响应按键输入来改变显示数字。

#include<reg52.h>

#define Dataport P1
unsigned char DuanMa[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71};
unsigned char WeiMa[] ={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};
unsigned char LED[] = {0xC0,0xF9,0xA4,0xB0,0x99,0x92,0x82,0xF8,0x80,0x90,0x88,0x83,0xC6,0xA1,0x86,0x8E};//共阳
unsigned char Tempdata[8];
sbit Latch_seg = P2^2;
sbit Latch_bit = P2^3;
sbit KEY1 = P0^0;
sbit KEY2 = P0^1;

void Timer_init()
{
TMOD = 0X01;
TH0 = 0x00;
TL0 = 0X00;
EA=1;
ET0=1;
TR0=1;

}

void Delayus(unsigned char t)
{
while(--t);
}
void Delayms(unsigned char t)
{
while(--t)
{
Delayus(245);
Delayus(245);
}
}

void display(unsigned char Firstbit,unsigned char num)//firstbit表示从第几个段开始,num表示位数
{
unsigned char i;

for (i=0;i<num;i++)
{
Dataport = 0;//清空数据，防止交替重影
Latch_seg = 1;
Latch_seg = 0;

Dataport = WeiMa[i+Firstbit];
Latch_bit = 1;
Latch_bit= 0;

Dataport = Tempdata[i];
Latch_seg = 1;
Latch_seg = 0;

Delayus(500);
}
}

/*void main()//共阳
{

unsigned char i = 0;
Timer_init();
P1 = 0xFF;
P0 = 0xff;
while(1)
{ P1=LED[i];
if(!KEY1 )
{
Delayms(10);
if(!KEY1)
{
while(!KEY1);
{

i++;
if(i == 10)
{
i = 0;
}
}

}
}

if(!KEY2 )
{

Delayms(10);
if(!KEY2)
{
while(!KEY2);
{

i--;
if(i == 0)
{
i = 9;
}
}

}
}
}
}*/

void main()
{

unsigned char i = 0;
Timer_init();
P1 = 0xFF;
P0 = 0xff;
while(1)
{
Tempdata[0] = DuanMa[i/10];
Tempdata[1] = DuanMa[i%10];
display(0,2);
if(!KEY1 )
{
Delayms(10);
if(!KEY1)
{
while(!KEY1);
{

i++;
if(i == 99)
{
i = 0;
}
}

}
}

if(!KEY2 )
{

Delayms(10);
if(!KEY2)
{
while(!KEY2);
{

i--;
if(i == 0)
{
i = 99;
}
}

}
}
}
}