double D_jw(double wd1,double jd1,double wd2,double jd2)
{
double x,y,out;
double PI=3.14159265;
double R=6.371229*1e6;
x=(jd2-jd1)*PI*R*cos( ((wd1+wd2)/2) *PI/180)/180;
y=(wd2-wd1)*PI*R/180;
out=hypot(x,y);
return out/1000;
}
从google maps的脚本里扒了段代码,没准啥时会用上。大家一块看看是怎么算的。
private const double EARTH_RADIUS = 6378.137;
private static double rad(double d)
{
return d * Math.PI / 180.0;
}
public static double GetDistance(double lat1, double lng1, double lat2, double lng2)
{
double radLat1 = rad(lat1);
double radLat2 = rad(lat2);
double a = radLat1 - radLat2;
double b = rad(lng1) - rad(lng2);
double s = 2 * Math.Asin(Math.Sqrt(Math.Pow(Math.Sin(a/2),2) +
Math.Cos(radLat1)*Math.Cos(radLat2)*Math.Pow(Math.Sin(b/2),2)));
s = s * EARTH_RADIUS;
s = Math.Round(s * 10000) / 10000;
return s;
}