Surprising Strings poj 3096 map的运用

最新推荐文章于 2019-11-07 16:46:32 发布

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本文介绍了一个关于字符串的独特性质——“SurprisingStrings”。通过定义D-pairs和D-unique概念，探讨了如何判断一个字符串是否对于所有可能的距离D都是独特的，并提供了一个实现此功能的示例代码。

Surprising Strings

Time Limit: 1000MS		Memory Limit: 65536K
Total Submissions: 6954		Accepted: 4502

Description

The D-pairs of a string of letters are the ordered pairs of letters that are distance D from each other. A string is D-unique if all of its D-pairs are different. A string is surprising if it is D-unique for every possible distance D.

Consider the string ZGBG. Its 0-pairs are ZG, GB, and BG. Since these three pairs are all different, ZGBG is 0-unique. Similarly, the 1-pairs of ZGBG are ZB and GG, and since these two pairs are different, ZGBG is 1-unique. Finally, the only 2-pair of ZGBG is ZG, so ZGBG is 2-unique. Thus ZGBG is surprising. (Note that the fact that ZG is both a 0-pair and a 2-pair of ZGBG is irrelevant, because 0 and 2 are different distances.)

Acknowledgement: This problem is inspired by the "Puzzling Adventures" column in the December 2003 issue of Scientific American.

Input

The input consists of one or more nonempty strings of at most 79 uppercase letters, each string on a line by itself, followed by a line containing only an asterisk that signals the end of the input.

Output

For each string of letters, output whether or not it is surprising using the exact output format shown below.

Sample Input

ZGBG
X
EE
AAB
AABA
AABB
BCBABCC
*

Sample Output

ZGBG is surprising.
X is surprising.
EE is surprising.
AAB is surprising.
AABA is surprising.
AABB is NOT surprising.
BCBABCC is NOT surprising.

#include<cstring>
#include<iostream>
#include<cstdio>
#include<algorithm>
using namespace std;
#include<map>
char s[80];
int main()
{
  while(scanf("%s",s)!=EOF)
  {
     if(s[0]=='*')
      break;
      int l=strlen(s);
      if(l<=2)
      {

        printf("%s is surprising.\n",s);
        continue;
      }
      int i,j;
      bool mark;
      for(i=0;i<l-1;i++)
      {
         mark=true;
          map<string,bool>sign;
         for(j=0;j<l-1-i;j++)
         {
          char p[2]={s[j],s[j+i+1]};
          if(sign[p]==false)
            {sign[p]=true;
              continue;
            }
            else
            {mark=false;break;
            }
         }
         if(mark==false)
           break;
      }
      if(mark)
       {printf("%s is surprising.\n",s);
      }
      else
      printf("%s is NOT surprising.\n",s);
  }
}