292. Nim Game

本文介绍了一种Nim游戏的胜负策略,通过分析游戏规则,得出当石堆中剩余石头数量能够被4整除时,先手玩家将无法赢得游戏的结论。文章还提供了一个简单的C++函数实现,用于判断在给定的初始石堆数量下,先手玩家是否能够获胜。

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You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to remove 1 to 3 stones. The one who removes the last stone will be the winner. You will take the first turn to remove the stones.

Both of you are very clever and have optimal strategies for the game. Write a function to determine whether you can win the game given the number of stones in the heap.

For example, if there are 4 stones in the heap, then you will never win the game: no matter 1, 2, or 3 stones you remove, the last stone will always be removed by your friend.

Hint:

  1. If there are 5 stones in the heap, could you figure out a way to remove the stones such that you will always be the winner?
  2. 最多能抓n个石头,那就%n+1为0则是必输的情况
class Solution {
public:
    bool canWinNim(int n) {
        if(n%4==0){
            return false;
        }else{
            return true;
        }
    }
};


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