题目描述【Leetcode】
Write a program that outputs the string representation of numbers from 1 to n.
But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.
Example:
n = 15,
Return:
[
“1”,
“2”,
“Fizz”,
“4”,
“Buzz”,
“Fizz”,
“7”,
“8”,
“Fizz”,
“Buzz”,
“11”,
“Fizz”,
“13”,
“14”,
“FizzBuzz”
]
这道题就是遇到3,5的倍数时输入Fizz和Buzz,其他就输入数字
class Solution {
public:
vector<string> fizzBuzz(int n) {
vector<string>s;
for(int i = 1; i <= n; i++){
if(i % 3 == 0 && i % 5 == 0) s.push_back("FizzBuzz");
else if(i%3 == 0) s.push_back("Fizz");
else if(i % 5 == 0) s.push_back("Buzz");
else s.push_back(to_string(i));
}
return s;
}
};
本文介绍了一个经典的编程面试题目——FizzBuzz问题。对于1到n之间的每个数字,如果该数字能被3整除,则输出Fizz;如果能被5整除,则输出Buzz;如果同时能被3和5整除,则输出FizzBuzz;否则直接输出该数字。
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