题目来源【Leetcode】
Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.
Do not allocate extra space for another array, you must do this in place with constant memory.
For example,
Given input array nums = [1,1,2],Your function should return length = 2, with the first two elements of nums being 1 and 2 respectively. It doesn’t matter what you leave beyond the new length.
这道题就是删除数组里重复的数字,直接用vector函数来做简单又省事;
class Solution {
public:
int removeDuplicates(vector<int>& nums) {
int s = nums.size();
nums.erase( unique(nums.begin(), nums.end() ), nums.end());
return nums.size();
}
};

本文介绍了一个LeetCode上的经典问题:如何在不使用额外空间的情况下移除已排序数组中的重复元素,并保持原有数组的顺序不变。文章提供了一种利用C++ STL中的unique方法结合vector容器来高效解决此问题的方法。
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