思路:把那张图打表(吐血...),然后就按照规则输出就行。
AC代码
#include <cstdio>
#include <cmath>
#include <cctype>
#include <algorithm>
#include <cstring>
#include <utility>
#include <string>
#include <iostream>
#include <map>
#include <set>
#include <vector>
#include <queue>
#include <stack>
using namespace std;
#pragma comment(linker, "/STACK:1024000000,1024000000")
#define eps 1e-10
#define inf 0x3f3f3f3f
#define PI pair<int, int>
typedef long long LL;
const int maxn = 50 + 5;
string a[maxn];
void init() {
for(int i = 0; i <= 35; ++i) {
if(i == 0) a[i] = ".-";
else if(i == 1) a[i] = "-...";
else if(i == 2) a[i] = "-.-.";
else if(i == 3) a[i] = "-..";
else if(i == 4) a[i] = ".";
else if(i == 5) a[i] = "..-.";
else if(i == 6) a[i] = "--.";
else if(i == 7) a[i] = "....";
else if(i == 8) a[i] = "..";
else if(i == 9) a[i] = ".---";
else if(i == 10) a[i] = "-.-";
else if(i == 11) a[i] = ".-..";
else if(i == 12) a[i] = "--";
else if(i == 13) a[i] = "-.";
else if(i == 14) a[i] = "---";
else if(i == 15) a[i] = ".--.";
else if(i == 16) a[i] = "--.-";
else if(i == 17) a[i] = ".-.";
else if(i == 18) a[i] = "...";
else if(i == 19) a[i] = "-";
else if(i == 20) a[i] = "..-";
else if(i == 21) a[i] = "...-";
else if(i == 22) a[i] = ".--";
else if(i == 23) a[i] = "-..-";
else if(i == 24) a[i] = "-.--";
else if(i == 25) a[i] = "--..";
else if(i == 26) a[i] = "-----";
else if(i == 27) a[i] = ".----";
else if(i == 28) a[i] = "..---";
else if(i == 29) a[i] = "...--";
else if(i == 30) a[i] = "....-";
else if(i == 31) a[i] = ".....";
else if(i == 32) a[i] = "-....";
else if(i == 33) a[i] = "--...";
else if(i == 34) a[i] = "---..";
else if(i == 35) a[i] = "----.";
}
for(int i = 0; i <= 35; ++i) {
string s = a[i];
a[i].clear();
for(int j = 0; j < s.size(); ++j) {
if(s[j] == '.') a[i].push_back('=');
else for(int k = 0; k < 3; ++k) a[i].push_back('=');
if(j < s.size()-1) a[i].push_back('.');
}
}
}
int main() {
init();
int T, n, kase = 1;
char s[25];
scanf("%d", &T);
while(T--) {
printf("Case #%d: ", kase++);
scanf("%d", &n);
for(int i = 0; i < n; ++i) {
scanf("%s", s);
for(int j = 0; j < strlen(s); ++j) {
s[j] = toupper(s[j]);
if(s[j] >= 'A' && s[j] <= 'Z') {
cout << a[s[j]-'A'];
}
else cout << a[s[j]-'0'+26];
if(j != strlen(s)-1) printf("...");
}
if(i != n-1) printf(".......");
}
printf("\n");
}
return 0;
}
如有不当之处欢迎指出!