python 已知平行四边形三个点，求第四个点

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原创最新推荐文章于 2026-04-07 09:23:40 发布 4.1k 阅读 AI 写同款· GEO 优化 ›

输出平行四边形图案（多种方案）问题描述：使用*在控制台打印平行四边形 例如：平行四边形中最长的一行输出的*是5个，则平行四边为：* ** *** **** ***** **** *** ** *方法1：把平行四边形分成上下两个部分，循环打印。参考代码：#include<stdio.h>int main() { int nStarNumber, i, j; printf("输入平行四边阅读详情

import numpy as np
#已知平行四边形三个点，求第四个点
#计算两点之间的距离
def CalcEuclideanDistance(point1,point2):
    vec1 = np.array(point1)
    vec2 = np.array(point2)
    distance = np.linalg.norm(vec1 - vec2)
    return distance
#计算第四个点
def CalcFourthPoint(point1,point2,point3): #pint3为A点
    D = (point1[0]+point2[0]-point3[0],point1[1]+point2[1]-point3[1])
    return D
#三点构成一个三角形，利用两点之间的距离，判断邻边AB和AC,利用向量法以及平行四边形法则，可以求得第四个点D
def JudgeBeveling(point1,point2,point3):
    dist1 = CalcEuclideanDistance(point1,point2)
    dist2 = CalcEuclideanDistance(point1,point3)
    dist3 = CalcEuclideanDistance(point2,point3)
    dist = [dist1, dist2, dist3]
    max_dist = dist.index(max(dist))
    if max_dist == 0:
        D = CalcFourthPoint(point1,point2,point3)
    elif max_dist == 1:
        D = CalcFourthPoint(point1,point3,point2)
    else:
        D = CalcFourthPoint(point2,point3,point1)
    return D

print(JudgeBeveling((0,1),(1,0),(1,1)))
print(JudgeBeveling((5,39),(500,35),(496,17)))

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