description
analysis
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暴力
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想象一下,当前矩阵的最左上角的111,如果不覆盖那么以后再没有机会去覆盖
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那么暴力覆盖就好了,边暴力边判断
code
#pragma GCC optimize("O3")
#pragma G++ optimize("O3")
#include<stdio.h>
#include<string.h>
#include<algorithm>
#define MAXN 1005
#define ll long long
#define reg register ll
#define fo(i,a,b) for (reg i=a;i<=b;++i)
#define fd(i,a,b) for (reg i=a;i>=b;--i)
#define O3 __attribute__((optimize("-O3")))
using namespace std;
ll f[MAXN][MAXN],g[MAXN][MAXN],h[MAXN][MAXN];
ll n,m,a,b,T,begx,begy;
char s[MAXN];
bool flag;
O3 inline ll read()
{
ll x=0,f=1;char ch=getchar();
while (ch<'0' || '9'<ch){if (ch=='-')f=-1;ch=getchar();}
while ('0'<=ch && ch<='9')x=x*10+ch-'0',ch=getchar();
return x*f;
}
O3 int main()
{
//freopen("T1.in","r",stdin);
T=read();
while (T--)
{
memset(f,0,sizeof(f)),memset(g,0,sizeof(g)),memset(h,0,sizeof(h));
n=read(),m=read(),a=read(),b=read(),begx=0,begy=0;
fo(i,1,n)
{
scanf("%s",s+1);
fo(j,1,m)f[i][j]=h[i][j]=s[j]-'0';
}
fo(i,1,a)
{
scanf("%s",s+1);
fo(j,1,b)
{
g[i][j]=s[j]-'0';
if (g[i][j] && begx==0 && begy==0)begx=i,begy=j;
}
}
flag=1;
fo(i,1,n)
{
fo(j,1,m)if (f[i][j]==1)
{
fo(k,begx,a)
{
fo(l,1,b)if (g[k][l])
{
ll xx=i+k-begx,yy=j+l-begy;
if (xx<1 || xx>n || yy<1 || yy>m || f[xx][yy]<1)
{
flag=0;
break;
}
--f[xx][yy];
}
if (!flag)break;
}
if (!flag)break;
}
if (!flag)break;
}
fo(i,1,n)
{
fo(j,1,m)if (f[i][j]!=0)
{
flag=0;
break;
}
if (!flag)break;
}
printf(flag?"YES\n":"NO\n");
}
return 0;
}