假设一段数字,第L项到第R项的和就等于前R项的和减去前L-1项的和。

本篇介绍了一个有趣的问题:Alyona如何通过选择母亲建议的花束子集来最大化自己的幸福感。文章详细解释了算法思路及其实现过程,并提供了完整的代码示例。

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赠(水)题一枚。不谢。
B. Alyona and flowers
time limit per test
2 seconds
memory limit per test
256 megabytes
input
standard input
output
standard output

Little Alyona is celebrating Happy Birthday! Her mother has an array of n flowers. Each flower has some mood, the mood of i-th flower isai. The mood can be positive, zero or negative.

Let's define a subarray as a segment of consecutive flowers. The mother suggested some set of subarrays. Alyona wants to choose several of the subarrays suggested by her mother. After that, each of the flowers will add to the girl's happiness its mood multiplied by the number of chosen subarrays the flower is in.

For example, consider the case when the mother has 5 flowers, and their moods are equal to 1,  - 2, 1, 3,  - 4. Suppose the mother suggested subarrays (1,  - 2)(3,  - 4)(1, 3)(1,  - 2, 1, 3). Then if the girl chooses the third and the fourth subarrays then:

  • the first flower adds 1·1 = 1 to the girl's happiness, because he is in one of chosen subarrays,
  • the second flower adds ( - 2)·1 =  - 2, because he is in one of chosen subarrays,
  • the third flower adds 1·2 = 2, because he is in two of chosen subarrays,
  • the fourth flower adds 3·2 = 6, because he is in two of chosen subarrays,
  • the fifth flower adds ( - 4)·0 = 0, because he is in no chosen subarrays.

Thus, in total 1 + ( - 2) + 2 + 6 + 0 = 7 is added to the girl's happiness. Alyona wants to choose such subarrays from those suggested by the mother that the value added to her happiness would be as large as possible. Help her do this!

Alyona can choose any number of the subarrays, even 0 or all suggested by her mother.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 100) — the number of flowers and the number of subarrays suggested by the mother.

The second line contains the flowers moods — n integers a1, a2, ..., an ( - 100 ≤ ai ≤ 100).

The next m lines contain the description of the subarrays suggested by the mother. The i-th of these lines contain two integers li and ri(1 ≤ li ≤ ri ≤ n) denoting the subarray a[li], a[li + 1], ..., a[ri].

Each subarray can encounter more than once.

Output

Print single integer — the maximum possible value added to the Alyona's happiness.

Examples
input
5 4
1 -2 1 3 -4
1 2
4 5
3 4
1 4
output
7
input
4 3
1 2 3 4
1 3
2 4
1 1
output
16
input
2 2
-1 -2
1 1
1 2
output
0
Note

The first example is the situation described in the statements.

In the second example Alyona should choose all subarrays.

The third example has answer 0 because Alyona can choose none of the subarrays.


贴上代码:
#include<stdio.h>
#include<string.h>
#include<algorithm>
#include<math.h>
using namespace std;
int a[105];
int main()
{
    int n,m;
    while(~scanf("%d%d",&n,&m))
    {
        for(int i=1; i<=n; i++)
        {
            scanf("%d",&a[i]);
            a[i]+=a[i-1];
        }
        int q,p;
        int sum=0;
        for(int i=0;i<m;i++)
        {
            scanf("%d%d",&q,&p);
            int s=a[p]-a[q-1];
            if(s>0)
            sum+=s;
        }
        printf("%d\n",sum);
    }
}


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