#include<iostream>
using namespace std;
int main()
{
long long int i,n,a[84]={0,1,199981,199982,199983,199984,199985,199986,199987,199988,199989,199990,200000,200001,1599981,1599982,1599983,1599984,1599985,1599986,1599987,1599988,1599989,1599990,2600000,2600001,13199998,35000000,35000001,35199981,35199982,35199983,35199984,35199985,35199986,35199987,35199988,35199989,35199990,35200000,35200001,117463825,500000000,500000001,500199981,500199982,500199983,500199984,500199985,500199986,500199987,500199988,500199989,500199990,500200000,500200001,501599981,501599982,501599983,501599984,501599985,501599986,501599987,501599988,501599989,501599990,502600000,502600001,513199998,535000000,535000001,535199981,535199982,535199983,535199984,535199985,535199986,535199987,535199988,535199989,535199990,535200000,535200001,1111111110};
cin>>n;
for(i=1;i<=83&&a[i]<n;i++)
{}
cout<<i-1<<" "<<a[i-1]<<endl;
return 0;
}
ACM JiLi Number
最新推荐文章于 2025-03-11 11:28:52 发布