【电子电路计算公式】 导线流过电流计算工具，我已经做成一个小工具了（源代码）

我想，在PCB设计中，导线的宽度选择很重要，如果知道导线最大能够流过多少电流的话，就方便多了。最近正打算设计一个温控器电路，用于控制【自制小冰箱】，其中功率是400W， 电流最大为33A， 电流很大，PCB设计的时候比较头痛，不过已经解决掉了。

 

直接在VS200X 中创建一个控制台项目（懒得做成界面了），建立一个C++源代码文件，编译，运行就OK了。

 

//------------------------------------------------------//
//(C)Copyright Debug 2009
//------------------------------------------------------//
//TODO: 计算导线所能流过的电流
//DATE: 2009/10
//REVR: 1.0
//------------------------------------------------------//
#include <stdio.h>
#include <math.h>

//----------------------------------------------//
//Attention: 这里是根据 IEC R40 表获得
//           2.11A/(mm * mm)
//----------------------------------------------//
#define C_LINE_A 2.11
#define PI 3.14159265358979

typedef struct _tag_cir_line
{
 double s;     //面积
 double i;     //所能流过的电流
}CIR_LINE, *LPCIR_LINE;

//-------------------------------------------------//
//Round
//-------------------------------------------------//

LPCIR_LINE ComputeRoundLineByRound(double r)
{
 LPCIR_LINE bk = new CIR_LINE;

 double s = PI * (r * r);
 
 bk->s = s;
 bk->i = s * C_LINE_A;

 return bk;
}

LPCIR_LINE ComputeLineByA(double i)
{
 LPCIR_LINE bk = new CIR_LINE;

 double s = i / C_LINE_A;

 bk->s = s;
 bk->i = i;

 return bk;
}

LPCIR_LINE ComputeRectLineByRect(double w, double h)
{
 LPCIR_LINE bk = new CIR_LINE;

 bk->s = w * h;
 bk->i = bk->s * C_LINE_A;

 return bk;
}

double ComputeRoundLineP(double inV, double inA, double r)
{
 LPCIR_LINE bk = ComputeRoundLineByRound(r);

 double p = inV * (inA - bk->i);

 delete bk;

 return p;
}

void main()
{
 int sel = 0;
 LPCIR_LINE tmp;
 double r, i;

 while (sel != 4){
  fflush(stdin);
  printf("(1) Compute By Round/r/n");
  printf("(2) Compute By A/r/n");
  printf("(3) Compute By Width Or Hight/r/n");
  printf("(4) Exit/r/n");
  printf("Please input your answer: ");
  scanf("%d", &sel);

  switch (sel)
  {
  case 1:
   {
    printf("/r/nInput Round: ");
    scanf("%lf", &r);

    tmp = ComputeRoundLineByRound(r);
    printf("> R = %0.2f A = %0.2f S = %0.2f mm*mm/r/n/r/n", r, tmp->i, tmp->s);
    delete tmp;

    break;
   }
  case 2:
   {
    printf("/r/nInput A: ");
    scanf("%lf", &i);

    tmp = ComputeLineByA(i);
    printf("> A = %0.2f S = %0.2f mm*mm/r/n", tmp->i, tmp->s);

    printf("If this line is round, then r = %0.2f mm/r/n", sqrt(tmp->s/PI));
    printf("Else this line is rectangle and height = 0.1mm then width = %0.2f mm/r/n", tmp->s/0.1);
    //-----------//
    //计算需要增厚厚度
    printf("[矩形]/r/n");
    printf("下面将要计算增厚厚度，所以请输入pcb导线宽度： ");
    scanf("%lf", &i);
    double s = i * 0.1;
    s = tmp->s - s;
    printf("以pcb导线宽度的80%%计算, 高度 %0.2f mm/r/n/r/n", s / (i * 0.8));
    printf("[圆形]/r/n");
    printf("直径 %0.2f mm/r/n/r/n", 2*sqrt(s/PI));

    delete tmp;

    break;
   }
  case 3:
   {
    printf("/r/nInput Width: ");
    scanf("%lf", &r);
    printf("/r/nInput Height: ");
    scanf("%lf", &i);

    tmp = ComputeRectLineByRect(r, i);
    printf("> A = %0.2f S = %0.2f mm*mm/r/n/r/n", tmp->i, tmp->s);
    delete tmp;

    break;
   }
  case 4:
    return;
  }
 }
}