chutzpah

问题:N! 结果零的个数分析:求零的个数即10的因子个数，而10=5*2即求5和2的对数记N! 的因子x个数为ans(x)显然在N! 中ans(2)>ans(5)则ans(10)=min(ans(2),ans(5))=ans(5)现在问题变为求ans(5)了那么还是继续分析N!成分N!数字 1 2 3 4 5 6 7 8 9 10 11 12 15 14 15

B. The Meeting Place Cannot Be Changedtime limit per test5 secondsmemory limit per test256 megabytesinputstandard inputoutputstandard outputThe main road in Byt

C. Molly’s Chemicals time limit per test2.5 seconds memory limit per test512 megabytes inputstandard input outputstandard output Molly Hooper has n different kinds of chemicals arranged in a line.

1001 数组中和等于K的数对

PieTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 16158 Accepted: 5497 Special JudgeDescriptionMy birthday is coming up and traditionally I'm ser

百小度是一个ACMer，也是一个超级赛亚人，每个ACMer都有一个战斗力，包括百小度。
所谓超级赛亚人的定义，是说如果在对抗中刚好接近极限状态，那就会激发斗志，实力提升. 具体来说，就是百小度现在要接受一些ACMer的挑战了，这些ACMer有n个人，第i个人的战斗力是aii。 
百小度接下来可以自主安排与这n个ACMer的PK顺序，他要想在PK赛中赢过另外一个ACMer，就必须使得自己的战斗力不小于

Problem Description One day, Dudu, the most clever boy, heard of ACM/ICPC, which is a very interesting game. He wants to take part in the game. But as we all know, you can’t get good result without te

描述 You are given an array a with n elements. Each element of a is either 0 or 1.Let’s denote the length of the longest subsegment of consecutive elements in a, consisting of only numbers one, as f(a).

描述 The annual Games in frogs’ kingdom started again. The most famous game is the Ironfrog Triathlon. One test in the Ironfrog Triathlon is jumping. This project requires the frog athletes to jump over

描述 A sequence of N positive integers (10 < N < 100 000), each of them less than or equal 10000, and a positive integer S (S < 100 000 000) are given. Write a program to find the minimal length of the

描述 给定序列A={A1,A2,…,An}A={A1,A2,…,An}, 要求改变序列A中的某些元素，形成一个严格单调的序列B（严格单调的定义为：Bi#include<stdio.h> #include<algorithm>using namespace std;int n,a[100005];bool check(int ans){ int last=a[0]-ans,now=

River HopscotchTime Limit: 2000MS Memory Limit: 65536K Total Submissions: 12303 Accepted: 5271 DescriptionEvery year the cows hold an event featuring a peculiar version of hopscotch that involves c

Chiaki Sequence Revisited http://acm.hdu.edu.cn/showproblem.php?pid=6304an={1an−an−1+an−1−an−2n=1,2n≥3an={1n=1,2an−an−1+an−1−an−2n≥3a_n=\begin{cases}1 &amp; n = 1,2 \\ a_{n - a_{n-1}} + a_{n-1 - a_{n-2}...