做法:求公共字串后DFS求出匹配点
#include <cstdio>
#include <cstring>
#define max(a, b) ((a) > (b) ? (a) : (b))
#define min(a, b) ((a) < (b) ? (a) : (b))
const int LMT = 105;
int dp[LMT][LMT], same[LMT], vis[LMT];
char seca[LMT], secb[LMT];
void dfs(int i, int j)
{
if(dp[i][j] == 0)return;
for(int ii = i; ii > 0; --ii)
for(int jj = j; jj > 0; --jj)
if(seca[ii] == secb[jj] && dp[ii][jj] == dp[i][j])
{
vis[ii] = jj;
dfs(ii - 1, jj - 1);
return;
}
return;
}
int main(void)
{
int i, j, lena, lenb;
seca[0] = secb[0] = 5;
while(~scanf("%s%s",&seca[1], &secb[1]))
{
lena = strlen(&seca[1]);
lenb = strlen(&secb[1]);
memset(dp, 0, sizeof(dp));
memset(vis, 0, sizeof(vis));
for(i = 1; i <= lena; ++i)
for(j = 1; j <= lenb; ++j)
{
if(seca[i] == secb[j]) dp[i][j] = dp[i-1][j-1] + 1;
dp[i][j] = max(dp[i][j], dp[i-1][j]);
dp[i][j] = max(dp[i][j], dp[i][j - 1]);
}
dfs(lena, lenb);
j = i = 1;
vis[lena + 1] = 5000;
while(i <= lena || j <= lenb)
{
for(;vis[i] == 0 && i <= lena; ++i)printf("%c",seca[i]);
for(;j < vis[i] && j <= lenb; ++j)printf("%c",secb[j]);
if(i <=lena) printf("%c",seca[i]);
++i;++j;
}
printf("\n");
}
return 0;
}