pycurl完成http_request

直接上源码：

#coding:utf-8


import pycurl
import StringIO


def http_request(url,data=None,headers={},timeout=None):
    buf = StringIO.StringIO()
    c = pycurl.Curl()


    c.setopt(pycurl.URL,url)
    c.setopt(pycurl.WRITEFUNCTION,buf.write)


    if timeout:
        c.setopt(pycurl.TIMEOUT,timeout)


    if data:
        c.setopt(pycurl.POSTFIELDS,data)


    c.setopt(pycurl.FOLLOWLOCATION,1)


    if headers:
        headers = ["%s:%s" % (k,v) for k,v in headers.iteritems()]
        c.setopt(pycurl.HTTPHEADER,headers)


    try:
        c.perform()
        code = c.getinfo(pycurl.RESPONSE_CODE)
    except IOError:
        print "Error!"


    return code,buf.getvalue()


print http_request("www.baidu.com")