*寒假水47——A + B Again

铁锅炖鱼，铜锅涮肉

于 2018-02-14 12:39:20 发布

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分类专栏： 2017寒假

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本文介绍了一个简单的十六进制加法问题及其解决方案。通过使用C语言编程，文章展示了如何读取两个十六进制整数，并计算它们的和，最后以十六进制的形式输出结果。

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There must be many A + B problems in our HDOJ , now a new one is coming. Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too. Easy ? AC it !

InputThe input contains several test cases, please process to the end of the file. Each case consists of two hexadecimal integers A and B in a line seperated by a blank. The length of A and B is less than 15.OutputFor each test case,print the sum of A and B in hexadecimal in one line. Sample Input

+A -A
+1A 12
1A -9
-1A -12
1A -AA

Sample Output

0
2C
11
-2C
-90

#include<stdio.h>

int main()
{
	long long a,b,c;
	while(scanf("%I64X%I64X",&a,&b)!=EOF){
		c=a+b;
		if(c>=0) printf("%I64X\n",c);
		   else printf("-%I64X\n",-c);
	}
	return 0;
}

题解：输出16进制形式：%I64X

有一个不懂的事情：还有一个酱紫的代码：

#include<stdio.h>

int main()
{
	long long a,b;
	while(scanf("%I64X%I64X",&a,&b)!=EOF){
	    printf("%I64X\n",a+b);
	}
	return 0;
}

但它的输出是：why??????