寒假水39——Treasure the new start, freshmen! 【结构体】

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本文介绍了一个简单的GPA计算器程序，该程序可以根据输入的成绩和学分计算学生的平均绩点（GPA）。如果任何一门课程的成绩低于60分，则认为GPA不存在。

"No pain, No Gain", HDU also has scholarship, who can win it? That's mainly rely on the GPA(grade-point average) of the student had got. Now, I gonna tell you the rule, and your task is to program to caculate the GPA.
If there are K(K > 0) courses, the i-th course has the credit Ci, your score Si, then the result GPA is
GPA = (C1 * S1 + C2 * S2 +……+Ci * Si……) / (C1 + C2 + ……+ Ci……) (1 <= i <= K, Ci != 0)
If there is a 0 <= Si < 60, The GPA is always not existed.

InputThe first number N indicate that there are N test cases(N <= 50). In each case, there is a number K (the total courses number), then K lines followed, each line would obey the format: Course-Name (Length <= 30) , Credits(<= 10), Score(<= 100).
Notice: There is no blank in the Course Name. All the Inputs are legalOutputOutput the GPA of each case as discribed above, if the GPA is not existed, ouput:"Sorry!", else just output the GPA value which is rounded to the 2 digits after the decimal point. There is a blank line between two test cases.
Sample Input

2
3
Algorithm 3 97
DataStruct 3 90
softwareProject 4 85
2
Database 4 59
English 4 81

Sample Output

90.10

Sorry!

#include<stdio.h>

struct tang{
	char course[100];
	double x,y;
}num[1000];

int main()
{
	int n,m,i,flag;
	double sum,t,ans;
	scanf("%d",&n);
	while(n--)
	{
		scanf("%d",&m);
		flag=1,sum=0,t=0;
		for(i=0;i<m;i++)
		{
			scanf("%s%lf%lf",num[i].course,&num[i].x,&num[i].y);
			if(num[i].y>=0&&num[i].y<60)
			{
				flag=0;
			}
			t+=num[i].x;
			sum+=num[i].x*num[i].y;
		}
		ans=sum/t;
		if(flag==1)
		{
			printf("%.2lf\n",ans);
		}
		else
		{
			printf("Sorry!\n");
		}
		if(n>0) printf("\n");
	}
	return 0;
}

题解：注意结构体的运用，再就没啥了。