*寒假水24——Fibbonacci Number

最新推荐文章于 2020-02-12 09:27:39 发布

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本文介绍了一个用于生成斐波那契数列的C++程序，该程序能够高效地处理0到50范围内的输入值。通过预先计算并存储斐波那契数列的前51项，避免了重复计算，显著提高了程序运行效率。

Your objective for this question is to develop a program which will generate a fibbonacci number. The fibbonacci function is defined as such:

f(0) = 0
f(1) = 1
f(n) = f(n-1) + f(n-2)

Your program should be able to handle values of n in the range 0 to 50.

InputEach test case consists of one integer n in a single line where 0≤n≤50. The input is terminated by -1.OutputPrint out the answer in a single line for each test case.Sample Input

Sample Output

2
3
5


        
  
you can use 64bit integer: __int64

#include<iostream>

using namespace std;

int main()
{
	int n,i;
	long long a[51]={0,1};
	for(i=2;i<51;i++)
	{
		a[i]=a[i-1]+a[i-2];
	}
	while(cin>>n&&n!=-1)
	{
		cout<<a[n]<<endl;
	}
	return 0;
}

题解：第好多好多遍写斐波那契呢~