Problem Description
To improve the organization of his farm, Farmer John labels each of his N (1 <= N <= 5,000) cows with a distinct serial number in the range 1..20,000. Unfortunately, he is unaware that the cows interpret some serial numbers as better than others. In particular,
a cow whose serial number has the highest prime factor enjoys the highest social standing among all the other cows.
(Recall that a prime number is just a number that has no divisors except for 1 and itself. The number 7 is prime while the number 6, being divisible by 2 and 3, is not).
Given a set of N (1 <= N <= 5,000) serial numbers in the range 1..20,000, determine the one that has the largest prime factor.
(Recall that a prime number is just a number that has no divisors except for 1 and itself. The number 7 is prime while the number 6, being divisible by 2 and 3, is not).
Given a set of N (1 <= N <= 5,000) serial numbers in the range 1..20,000, determine the one that has the largest prime factor.
Input
* Line 1: A single integer, N
* Lines 2..N+1: The serial numbers to be tested, one per line
* Lines 2..N+1: The serial numbers to be tested, one per line
Output
* Line 1: The integer with the largest prime factor. If there are more than one, output the one that appears earliest in the input file.
Sample Input
4 36 38 40 42
Sample Output
38
找到最大的素数因子
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#define maxn 20003
using namespace std;
int isPrime(int n)
{
int i;
int b = sqrt(n);
for(i = 2; i <= b; i++)
if(n % i == 0)
return 0;
return 1;
}
int pre_solve(int n)
{
int temp1=1;
for(int i=1;i<=n;i++)
{
if(n%i==0&&isPrime(i))
temp1=i;
}
return temp1;
}
int main()
{
int ncase;
int num,ans,maxn1,temp;
while(~scanf("%d",&ncase))
{
temp=ans=maxn1=0;
while(ncase--)
{
scanf("%d",&num);
ans=pre_solve(num);
if(ans>temp)
{
temp=ans;
maxn1=num;
}
}
printf("%d\n",maxn1);
}
return 0;
}