Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 11601 Accepted Submission(s): 3673
Problem Description
To improve the organization of his farm, Farmer John labels each of his N (1 <= N <= 5,000) cows with a distinct serial number in the range 1..20,000. Unfortunately, he is unaware that the cows interpret some serial numbers as better than others. In particular, a cow whose serial number has the highest prime factor enjoys the highest social standing among all the other cows.
(Recall that a prime number is just a number that has no divisors except for 1 and itself. The number 7 is prime while the number 6, being divisible by 2 and 3, is not).
Given a set of N (1 <= N <= 5,000) serial numbers in the range 1..20,000, determine the one that has the largest prime factor.
Input
* Line 1: A single integer, N
* Lines 2..N+1: The serial numbers to be tested, one per line
Output
* Line 1: The integer with the largest prime factor. If there are more than one, output the one that appears earliest in the input file.
Sample Input
4 36 38 40 42
Sample Output
38
Source
题解:求出N个数中,有最大质因子的数。
#include<cstdio>
#include<cstring>
#include<iostream>
#include<cmath>
using namespace std;
#define n 20017
int pri[n];
void prime(){//打表
pri[1]=1;
for (int i=2;i<=n; i++) {
if (!pri[i]) {
for (int j=i;j<=n; j=j+i) {
pri[j]=i;//更新j数中最大的素数
}
}
}
return ;
}
int main(){
prime();
int t,m;
while (cin>>t) {
int ans=0;
int maxx=-1;
for (int i=0; i<t; i++) {
cin>>m;
if (pri[m]>maxx) {
maxx=pri[m];
ans=m;
}
}
cout<<ans<<endl;
}
return 0;