教你用python开发一个性格分析工具_python人物性格分析-优快云博客

俗话说:“龙生九子,子子不同”。通过九型人格的性格分析工具，将性格心理与行为划分为九类。再对不同性格的人群进行研究分析，找到每一类人最适合岗位与职责。这就是领导者们运筹与帷幄之中，决胜于千里之外的筹码。

人为刀俎，我为鱼肉。不想受制于领导者们的掌控，首先要了解自身的人格分类，才能完善自己的不足。这该如何下手？作为程序员，让我们用代码完成自我的救赎吧！

大家可以通过下面测试初步了解下自己是什么性格类型：

https://wenku.baidu.com/view/19455024dd36a32d72758105.html

测试题总共36道，通过各场景下的行为表现，最终分析出你最接近的人格分类。现在题有了，如何做出测试题呢？我选择使用Python的tkinter模块，将测试题开发为一个可执行的exe工具，说干就干！

界面无需太过复杂，提供说明、题目、选项作答、题目切换与操作按钮即可。当然，交卷后，需要显示用户的测试结果，那么开始吧！

30 minutes later...完成！

# -*- coding: utf-8 -*-
# @Author   : 王翔
# @微信号   : King_Uranus
# @公众号    : 清风Python
# @GitHub   : BreezePython - Overview
# @Date     : 2019/11/12 23:12
# @Software : PyCharm
# @version  ：Python 3.7.3
# @File     : Enneagram_GUI.py
 
 
# coding:utf-8
from tkinter import *
import Enneagram_Exam
import Enneagram_Result
import tkinter.messagebox
 
# 自测说明
Standard = '此份问卷共有36道测试题目，请在每题中选择你认为最恰当或者最接近描述自己的性格行为的句子，\n' \
           '请全部作答，最高分的项目很可能成为你的基本性格型态。'
 
# 人格类型矩阵
Style_Dict = [
    {3: 2, 6: 2, 10: 2, 15: 2, 19: 1, 22: 2, 28: 2, 32: 2},
    {1: 1, 6: 1, 12: 1, 17: 2, 20: 1, 23: 1, 29: 1, 33: 1},
    {4: 1, 7: 1, 10: 1, 14: 2, 23: 2, 26: 2, 30: 1, 34: 1},
    {2: 1, 8: 2, 12: 2, 16: 1, 21: 2, 24: 1, 28: 1, 34: 2},
    {1: 2, 4: 2, 13: 1, 16: 2, 19: 2, 25: 1, 31: 1, 36: 1},
    {5: 1, 9: 2, 14: 1, 18: 1, 21: 1, 25: 2, 29: 2, 32: 1},
    {2: 2, 7: 2, 11: 2, 18: 2, 22: 1, 27: 2, 33: 2, 36: 2},
    {3: 1, 9: 1, 13: 2, 17: 1, 24: 2, 27: 1, 20: 2, 35: 2}
]
 
 
class ExamPage:
    def __init__(self, master=None):
        self.root = master
        # 用户结果集
        self.user_result = {}
        self.status = 1
        self.All_Exam = Enneagram_Exam
        self.normal_choice = IntVar()
        self.start_exam()
 
    # 上一题方法
    def before(self):
        if self.normal_choice.get() != 0:
            self.user_result[self.status] = self.normal_choice.get()
            if self.status > 1:
                self.status -= 1
                self.body.grid_forget()
                self.main_exam()
        else:
            tkinter.messagebox.showwarning("提示：", message="请先选择答案！")
 
    # 下一题方法
    def after(self):
        if self.normal_choice.get() != 0:
            self.user_result[self.status] = self.normal_choice.get()
            if self.status < len(Enneagram_Exam.Exam):
                self.status += 1
                self.body.grid_forget()
                self.main_exam()
        else:
            tkinter.messagebox.showwarning("提示：", message="请先选择答案！")
 
    # 获取当前题目
    def exam_files(self, num):
        return list(map(lambda x: x.split('.'), self.All_Exam.Exam[num - 1].strip().split('\n')))
 
    # 交卷
    def hand_paper(self):
        self.user_result[self.status] = self.normal_choice.get()
        if len(self.user_result) != 36:
            tkinter.messagebox.showwarning("提示：", message="您还有未完成的测试题！")
        else:
            self.exam_result = LabelFrame(self.root, text="测试结果", padx=10, pady=10, fg="red", font=("黑体", '11'))
            self.exam_result.grid(padx=10, pady=5, sticky=NSEW)
            sc = Scrollbar(self.exam_result)
            sc.grid(row=0, column=1, sticky=NS)
            result_info = Text(self.exam_result, font=("黑体", '11'), width=85, yscrollcommand=sc.set)
            result_info.grid(row=0, column=0, sticky=NSEW)
            sc.config(command=result_info.yview)
            all_num = []
            for style in Style_Dict:
                calc_num = list(
                    point for point in self.user_result if point in style and self.user_result[point] == style[point])
                if calc_num == None:
                    all_num.append(0)
                else:
                    all_num.append(len(calc_num))
            user_type = all_num.index(max(all_num))
            for line in Enneagram_Result.Result[user_type]:
                result_info.insert(END, line)
 
    # 启动测试所需控制按钮
    def start_exam(self):
        self.title = LabelFrame(self.root, text="自测说明", padx=10, pady=10, fg="red", font=("黑体", '11'))
        self.title.grid(padx=10, pady=5)
        note = Label(self.title, text=Standard, justify=LEFT, font=("黑体", '11'))
        note.grid()
        self.show = LabelFrame(self.root, text="选项", padx=10, pady=10, fg="red", font=("黑体", '11'))
        self.show.grid(padx=10, pady=5, sticky=EW)
        go_back = Button(self.show, text="上一题", width=8, command=lambda: self.before())
        go_back.grid(row=4, column=0, padx=5, pady=10)
        to_forword = Button(self.show, text="下一题", width=8, command=lambda: self.after())
        to_forword.grid(row=4, column=1, padx=5, pady=10, sticky=E)
        hand_in = Button(self.show, text="交卷", width=8, command=lambda: self.hand_paper())
        hand_in.grid(row=4, column=2, padx=5, pady=10, sticky=E)
        exit_sys = Button(self.show, text="退出", width=8, command=lambda: sys.exit())
        exit_sys.grid(row=4, column=3, padx=5, pady=10, sticky=E)
        self.main_exam()
 
    # 测试题主界面
    def main_exam(self):
        self.normal_choice.set(0)
        self.body = LabelFrame(self.root,
                               text="测试题  第%s题，剩余%s题" % (self.status, (len(Enneagram_Exam.Exam) - self.status)),
                               padx=10, pady=10, fg="red", font=("黑体", '11'))
        self.body.grid(padx=10, pady=5, sticky=EW)
        for option, choice in self.exam_files(self.status):
            authority_choice = Radiobutton(self.body, text=choice, variable=self.normal_choice, value=option)
            authority_choice.grid(row=option, sticky=W)
        Label(self.body, text="  第%s道题，用户选择的结果是：" % self.status, fg="red", font=("黑体", '11')).grid(row=3, column=0,
                                                                                                   sticky=W)
        Label(self.body, textvariable=self.normal_choice).grid(row=3, column=0, sticky=E)

进下面链接，学习更多python小技巧。

https://note.youdao.com/ynoteshare1/index.html?id=c13123e7b1264fd5d2320dae01e0cf1a&type=note