List一次删除多个值

最新推荐文章于 2023-08-02 14:37:41 发布

bohu83

最新推荐文章于 2023-08-02 14:37:41 发布

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分类专栏： java 文章标签： list 删除多个 jdk8

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jdk 1.6时候，list删除值容易出错，就是直接使用：

list.remove(i);

所以要使用迭代器：

     ArrayList<String> strList = Lists.newArrayList("a","b","c");
        Iterator<String> iterator = strList.iterator();
        while (iterator.hasNext()){
            String i = iterator.next();
            if(i.equals("c")){
                iterator.remove();
            }
        }
        System.out.println(strList);

输出：a,b

如果jdk 8之后。使用新的方法会更灵活，单个值可以使用：

removeIf

多个值也可以使用：stream表达式的filter：

 public static void main(String[] args) {

        List<Department>  list = new ArrayList<>();
       for(int i=0;i<7;i++) {
           Department depart = new Department();
           depart.setDepartCode("code_"+i);
           depart.setId(i );
           depart.setName("测试_"+i);
           list.add(depart);
       }
       System.out.println("init:"+JSON.toJSONString(list));

       //to dellist
        List<String> removdeList = new ArrayList<>();
        removdeList.add("code_3");
        removdeList.add("code_4");
        removdeList.add("code_5");
        list = list.stream().filter(dep->!removdeList.contains(dep.getDepartCode() ) ).collect(Collectors.toList()) ;
        System.out.println("after delete:"+JSON.toJSON( list) );
    }

init:[{"departCode":"code_0","id":0,"name":"测试_0"},{"departCode":"code_1","id":1,"name":"测试_1"},{"departCode":"code_2","id":2,"name":"测试_2"},{"departCode":"code_3","id":3,"name":"测试_3"},{"departCode":"code_4","id":4,"name":"测试_4"},{"departCode":"code_5","id":5,"name":"测试_5"},{"departCode":"code_6","id":6,"name":"测试_6"}]
after delete:[{"name":"测试_0","departCode":"code_0","id":0},{"name":"测试_1","departCode":"code_1","id":1},{"name":"测试_2","departCode":"code_2","id":2},{"name":"测试_6","departCode":"code_6","id":6}]

filter除了单个的判断外，项这种：

    list= list.stream().filter(l -> l != num).collect(Collectors.toList());

还可以上面那种的使用list去除多个。