计算 斐波那契数列(Fibonacci sequence),不受长整型位数限制。
编写 fibonacci.py 如下
# -*- coding: utf-8 -*-
""" 计算 斐波那契数列(Fibonacci sequence)"""
import sys
from datetime import datetime
# 递归函数定义
def fib(n):
if n <=0: return 0
if n ==1: return 1
if n ==2: return 1
return fib(n-1) + fib(n-2)
# 将递归改为迭代可以把效能提升不少
def fib1(n):
x,y = 0,1
while n>0:
x,y = y,x+y
n = n-1
return x
# 通过将计算结果保存到 dict中,后面计算时可以取用,称为备忘方式
known = {0:0, 1:1, 2:1}
def fib2(n):
if n <=0: return 0
if n in known: return known[n]
res = fib2(n-1) + fib2(n-2)
known[n] = res
return res
# main()
if len(sys.argv) ==2:
n = int(sys.argv[1])
else:
print(' usage: python fibonacci.py n ')
sys.exit(1)
if n < 3:
print(' input n >= 3 ')
else:
print(datetime.now())
print('fib1(%d)= %d' % (n, fib1(n)))
print(datetime.now())
print('fib2(%d)= %d' % (n, fib2(n)))
print(datetime.no