Assign Cookies

本文介绍了一种通过双指针技巧解决分配饼干问题的方法。该问题的目标是在给定每个孩子的贪婪系数和每块饼干大小的情况下,最大化满足的孩子数量。文章详细解释了算法步骤,并提供了示例输入输出。

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Assume you are an awesome parent and want to give your children some cookies. But, you should give each child at most one cookie. Each child i has a greed factor gi, which is the minimum size of a cookie that the child will be content with; and each cookie j has a size sj. If sj >= gi, we can assign the cookie j to the child i, and the child i will be content. Your goal is to maximize the number of your content children and output the maximum number.

Note:
You may assume the greed factor is always positive. 
You cannot assign more than one cookie to one child.

Example 1:

Input: [1,2,3], [1,1]

Output: 1

Explanation: You have 3 children and 2 cookies. The greed factors of 3 children are 1, 2, 3. 
And even though you have 2 cookies, since their size is both 1, you could only make the child whose greed factor is 1 content.
You need to output 1.

Example 2:

Input: [1,2], [1,2,3]

Output: 2

Explanation: You have 2 children and 3 cookies. The greed factors of 2 children are 1, 2. 
You have 3 cookies and their sizes are big enough to gratify all of the children, 
You need to output 2.

这道题感觉跟情景没什么关系,分别用两个指针 index1, index2指向这两个已经按照从小到大的顺序排列好的数组的头,然后开始找,如果nums2[index2] >= nums1[index1], 那么可以把index2这个cookie分配过去,index1++, index2++; 否则,index2++。


代码:

public int findContentChildren(int[] g, int[] s) {
        Arrays.sort(g);
        Arrays.sort(s);
        int index1 = 0;
        int index2 = 0;
        while(index1<g.length && index2<s.length){
            if(s[index2]>=g[index1]){
                index2++;
                index1++;
            }else{
                index2++;
            }
        }
        return index1;
    }


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