问题描述
FJ在沙盘上写了这样一些字符串:
A1 = “A”
A2 = “ABA”
A3 = “ABACABA”
A4 = “ABACABADABACABA”
… …
你能找出其中的规律并写所有的数列AN吗?
输入格式
仅有一个数:N ≤ 26。
输出格式
请输出相应的字符串AN,以一个换行符结束。输出中不得含有多余的空格或换行、回车符。
样例输入
3
样例输出
ABACABA
import java.util.Scanner;
public class ABA {
public
static void main(String[] args) {
Scanner
sc=new Scanner(System.in);
int
n=sc.nextInt();
arrayMethod(n);
}
public static void arrayMethod(int n){
String[]
s1={"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
String[]
s2={"A"};
if(n==1)printArray(s2);//如果输入1,直接输出A
else{
for(int
i=2;i<=n;i++){
s2=Method(s2,s1[i-1]);
}
printArray(s2);
}
}
public
static String[] Method(String[] s,String s2){//返回一个数组为:两边是数组s,中间是s2
String[] str=new
String[s.length*2+1];
for(int i=0;i<s.length;i++){
str[i]=s[i];
}
str[s.length]=s2;
for(int i=0;i<s.length;i++){
str[i+s.length+1]=s[i];
}
return str;
}
public
static void printArray(String[] st){//打印数组,每100行换一行
for(int
i=0;i<st.length;i++){
if(i%100==0)
System.out.println();
System.out.print(st[i]);
}
}
}