//每一行增加的个数是欧拉函数的2倍
#include<stdio.h>
#define N 1000001
int a[N],b[N];
int main()
{
int i,j,n;
__int64 sum;
for(i=2;i<N;i++)
a[i]=i;
for(i=2;i<N;i++)
{
if(b[i]==1)continue;
a[i]=i-1;
for(j=i+i;j<N;j+=i)
{
b[j]=1;
a[j]=a[j]/i*(i-1);
}
}
while(scanf("%d",&n)!=-1)
{
sum=3;
for(i=1;i<=n;i++)
sum+=2*a[i];
printf("%I64d\n",sum);
}
return 0;
}