HDU6066-RXD's date

本文介绍了一个简单的程序设计问题,即根据未来若干天的温度预测数据,计算并输出适宜外出约会的日子数量。输入包括天数及每天的预计温度,输出为温度低于或等于35度的天数。

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RXD's date

                                                                        Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others)
                                                                                                  Total Submission(s): 645    Accepted Submission(s): 490


Problem Description
As we all know that RXD is a life winner, therefore he always goes out, dating with his female friends.
Nevertheless, it is a pity that his female friends don't like extremely hot temperature. Due to this fact, they would not come out if it is higher than 35 degrees.
RXD is omni-potent, so he could precisely predict the temperature in the next  t  days, but he is poor in counting.
He wants to know, how many days are there in the next  t  days, in which he could go out and date with his female friends.
 

Input
There is only one test case.

The first line consists of one integer  t .

The second line consists of  t  integers  ci  which means the temperature in the next  t  days.

1t1000  

0ci50
 

Output
Output an integer which means the answer.
 

Sample Input
  
5 33 34 35 36 37
 

Sample Output
  
3
 

Source
 

题意:给出n个数字,求出有多少个数字小于等于35


#include <iostream>
#include <cstdio>
#include <cstring>
#include <string>
#include <algorithm>
#include <map>
#include <set>
#include <stack>
#include <queue>
#include <vector>
#include <bitset>
#include <functional>

using namespace std;

#define LL long long
const int INF = 0x3f3f3f3f;

int n,a[1009];

int main()
{
    while(~scanf("%d",&n))
    {
        int sum=0;
        for(int i=1;i<=n;i++)
        {
            scanf("%d",&a[i]);
            if(a[i]<=35) sum++;
        }
        printf("%d\n",sum);
    }
    return 0;
}

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