ZOJ2201-No Brainer

最新推荐文章于 2018-05-24 16:25:23 发布

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最新推荐文章于 2018-05-24 16:25:23 发布

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本文介绍了一道趣味编程题目——僵尸吃脑谜题。题目要求比较僵尸所吃的脑数量与其生存所需的脑数量，并据此输出相应的结果。示例代码使用了 C 语言实现，通过简单的条件判断来解决问题。

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No Brainer

Time Limit: 2 Seconds Memory Limit: 65536 KB

Zombies love to eat brains. Yum.

Input

The first line contains a single integer n indicating the number of data sets.

The following n lines each represent a data set. Each data set will be formatted according to the following description:

A single data set consists of a line "X Y", where X is the number of brains the zombie eats and Y is the number of brains the zombie requires to stay alive.

Output

For each data set, there will be exactly one line of output. This line will be "MMM BRAINS" if the number of brains the zombie eats is greater than or equal to the number of brains the zombie requires to stay alive. Otherwise, the line will be "NO BRAINS".

Sample Input

3
4 5
3 3
4 3

Sample Output

NO BRAINS
MMM BRAINS
MMM BRAINS

Source: South Central USA 2004

题意：输入两个数，比大小输出结果

#include <iostream>
#include <cstdio>
#include <cstring>
#include <string>
#include <algorithm>
#include <cmath>
#include <map>
#include <set>
#include <stack>
#include <queue>
#include <vector>
#include <bitset>

using namespace std;

#define LL long long
const int INF=0x3f3f3f3f;

int main()
{
  int t,a,b;
  scanf("%d",&t);
  while(t--)
  {
    scanf("%d%d",&a,&b);
    if(a>=b) printf("MMM BRAINS\n");
    else printf("NO BRAINS\n");
  }
    return 0;
}