Given a binary tree, you need to compute the length of the diameter of the tree. The diameter of a binary tree is the length of the longestpath between any two nodes in a tree. This path may or may not pass through the root.
Example:
Given a binary tree
1 / \ 2 3 / \ 4 5
Return 3, which is the length of the path [4,2,1,3] or [5,2,1,3].
求最大距离的两个节点。左右子树的长度之和为当前子树的最大Diameter, 左右子树较大值+1为当前子树长度,递归求得整颗数的最大Diameter
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
int ans = 0;
public int diameterOfBinaryTree(TreeNode root) {
length(root);
return ans;
}
private int length(TreeNode root){
if(root==null) return 0;
int left = length(root.left);
int right = length(root.right);
ans = Math.max(ans, left+right);
return 1+Math.max(left, right);
}
}