leetcode 561. Array Partition I

Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible.

Example 1:

Input: [1,4,3,2]

Output: 4
Explanation: n is 2, and the maximum sum of pairs is 4.

Note:

1. n is a positive integer, which is in the range of [1, 10000].
2. All the integers in the array will be in the range of [-10000, 10000].

题目没看懂。。。结果就是求和一对中的最小值，排序取单数项即可

public class Solution {
    public int arrayPairSum(int[] nums) {
        Arrays.sort(nums);
        
        int sum=0;
        for(int i=0; i<nums.length; i+=2){
            sum += nums[i];
        }
        return sum;
    }
}