ZCMU2205 Chord

本文探讨了音乐理论中的音阶、音符与和弦概念,详细解析了如何通过算法识别三和弦的类型,包括大三和弦、小三和弦以及无法归类的和弦。通过具体的例子和代码实现,展示了如何判断和弦的性质。

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Description

Vasya studies music.

He has learned lots of interesting stuff. For example, he knows that there are 12 notes: C, C#, D, D#, E, F, F#, G, G#, A, B, H. He also knows that the notes are repeated cyclically: after H goes C again, and before Cstands H. We will consider the C note in the row's beginning and the C note after the H similar and we will identify them with each other. The distance between the notes along the musical scale is measured in tones: between two consecutive notes there's exactly one semitone, that is, 0.5 tone. The distance is taken from the lowest tone to the uppest one, that is, the distance between C and E is 4 semitones and between E and C is 8 semitones

Vasya also knows what a chord is. A chord is an unordered set of no less than three notes. However, for now Vasya only works with triads, that is with the chords that consist of exactly three notes. He can already distinguish between two types of triads − major and minor.

Let's define a major triad. Let the triad consist of notes XY and Z. If we can order the notes so as the distance along the musical scale between X and Y equals 4 semitones and the distance between Y and Z is 3 semitones, then the triad is major. The distance between X and Z, accordingly, equals 7 semitones.

A minor triad is different in that the distance between X and Y should be 3 semitones and between Y and Z − 4 semitones.

For example, the triad "C E G" is major: between C and E are 4 semitones, and between E and G are 3 semitones. And the triplet "C# B F" is minor, because if we order the notes as "B C# F", than between B and C#will be 3 semitones, and between C# and F − 4 semitones.

Help Vasya classify the triad the teacher has given to him.

Input

The only line contains 3 space-separated notes in the above-given notation.

Output

Print "major" if the chord is major, "minor" if it is minor, and "strange" if the teacher gave Vasya some weird chord which is neither major nor minor. Vasya promises you that the answer will always be unambiguous. That is, there are no chords that are both major and minor simultaneously.

Examples

Input

C E G

Output

major

Input

C# B F

Output

minor

Input

A B H

Output

strange

代码

#include<iostream>
#include<algorithm>
#include<stdio.h>
#include<string.h>
using namespace std;
struct node
{
    char stuff[5];
    int n;
} e[5];
int check(node e)
{
    if(strcmp(e.stuff,"C")==0)
        return 1;
    else if(strcmp(e.stuff,"C#")==0)
        return 2;
    else if(strcmp(e.stuff,"D")==0)
        return 3;
    else if(strcmp(e.stuff,"D#")==0)
        return 4;
    else if(strcmp(e.stuff,"E")==0)
        return 5;
    else if(strcmp(e.stuff,"F")==0)
        return 6;
    else if(strcmp(e.stuff,"F#")==0)
        return 7;
    else if(strcmp(e.stuff,"G")==0)
        return 8;
    else if(strcmp(e.stuff,"G#")==0)
        return 9;
    else if(strcmp(e.stuff,"A")==0)
        return 10;
    else if(strcmp(e.stuff,"B")==0)
        return 11;
    else if(strcmp(e.stuff,"H")==0)
        return 12;
}
int judge(int x,int y,int z)
{
    int difx=(y-x+12)%12;
    int dify=(z-y+12)%12;
    int difz=(z-x+12)%12;
    if(difx==4&&dify==3&&difz==7)
        return 1;
    else if(difx==3&&dify==4)
        return 2;
    return 0;
}
int main()
{
    while(~scanf("%s %s %s",e[0].stuff,e[1].stuff,e[2].stuff))
    {
        for(int i=0; i<3; i++)
        {
            e[i].n=check(e[i]);
        }
        int x=e[0].n,y=e[1].n,z=e[2].n;
        if(judge(x,y,z)==1||judge(x,z,y)==1||judge(y,x,z)==1||judge(y,z,x)==1||judge(z,x,y)==1||judge(z,y,x)==1)
            printf("major\n");
        else if(judge(x,y,z)==2||judge(x,z,y)==2||judge(y,x,z)==2||judge(y,z,x)==2||judge(z,x,y)==2||judge(z,y,x)==2)
            printf("minor\n");
        else
            printf("strange\n");
    }
    return 0;
}

 

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