1019 General Palindromic Number (20分)（一个字水）

1019 General Palindromic Number (20分)

代码

#include<iostream>
#include<vector>
using namespace std;
int main() {
 int a, b;
 vector<int>v;
 scanf("%d %d", &a, &b);
 while (a != 0) {
  v.push_back(a % b);
  a /= b;
 }
 bool tag = true;
 for (int i = 0; i < v.size() / 2; ++i)
  if (v[i] != v[v.size() - 1 - i])tag = false;
 printf("%s\n", tag ? "Yes" : "No");
 for (int i = v.size() - 1; i >= 0; --i)
  printf("%d%s", v[i], i == 0 ? "" : " ");
 return 0;
}