1002 A+B for Polynomials (25分)(一个字短!)

飞腾D2000 BIOS编译避坑指南:PCIE拆分、S3电源与过温保护配置详解 本文详细解析飞腾D2000 BIOS编译中的关键配置技巧,包括PCIE拆分模式优化、S3电源管理适配及过温保护设置。通过实战案例和参数调优建议,帮助开发者规避常见陷阱,充分发挥国产高性能计算平台的硬件潜力。特别针对BIOS编译过程中的隐蔽问题提供解决方案。 阅读详情

1002 A+B for Polynomials (25分)

题目

This time, you are supposed to find A+B where A and B are two polynomials.
Input Specification:
Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N​1​​ aN​1​​​​ N​2​​ a​N​1… Nk​​ aN​k where K is the number of nonzero terms in the polynomial, N​i​​ and a​N​i​​ (i=1,2,⋯,K) are the exponents and coefficients, respectively. It is given that 1≤K≤10,0≤N​K​​<⋯<N2​​​​<N1​​​​≤1000.
Output Specification:
For each test case you should output the sum of AAA and BBB in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.

Sample Input:
2 1 2.4 0 3.2
2 2 1.5 1 0.5

Sample Output:
3 2 1.5 1 2.9 0 3.2

题意

多项式相加

分析

用double数组保存,并相加,最后计数非零项并按照格式输出

代码

#include<iostream>
using namespace std;
double co[1010], d;
int n, a, m = 0, cnt = 0;
int main() {
 	for (int i = 0; i < 2; ++i) {
  		scanf("%d", &n);
  		for (int j = 0; j < n; ++j) {	
			scanf("%d %lf", &a, &d);
   			m = m < a ? a : m;
   			co[a] += d;
  		}
 	}
 	for (int i = m; i >= 0; --i)
  	if (co[i] != 0)++cnt;
 	printf("%d", cnt);
 	for (int i = m; i >= 0; --i)
  		if (co[i] != 0)printf(" %d %.1lf", i, co[i]);
 	return 0;
}
openHarmony之AI Engine:万字讲解如何在应用、开发板上接入AI大模型调用 本文章介绍如何在 OpenHarmony 开发板上集成和部署各类 AI 大模型,实现终端直接聊天功能,并为语音助手、智能机器人等应用提供 AI 接口支持。 阅读详情

相关推荐

GB/T 27930-2023协议升级与CANoe仿真测试实践

本文深入解析GB/T 27930-2023协议的核心升级,包括A/B类系统分类与EVIN码引入,并详细指导如何使用CANoe搭建仿真测试环境、编写CAPL脚本及利用DLL库进行一致性验证与故障注入测试,助力开发人员确保电动汽车充电通信的合规性与稳定性。

y7z8a的博客 541

动态规划区间调度问题

题目描述 Problem description Given N activities A=A1,A2,…,ANA=A1,A2,…,AN that wish to use a resource. Each activity AiAi uses the resource during interval [Si,Fi)[Si,Fi). The selection of activity AiAi yields a benefit of WiWi. To select a collection of compat

神奇的木木的博客 616

单片机如何获得5V电源

在单片机实际设计中,有时会需要在电路中用到5V电压源,那么这个常见的实验需求有哪些办法解决呢,我综合网上的资料,概括一下: 1)USB    这种方法在我们直接将单片机板与电脑连接调试的时候,算是简单又方便的办法了,但如果我所要得到的成品不直接连接外部的器件,这就得舍弃。     常用的,USB/5V插头线,这是一种专门的电源线,一端是USB通用接口,可以直插USB端口,另一端是内正外负电压

Echo_Ana的博客 3万+

C语言动态规划(2)___Maximum sum

Description Given a set of n integers: A={a1, a2,..., an}, we define a function d(A) as below: Your task is to calculate d(A). Input The input consists of T( Each test case co

YzlCoder的记事本 1407

【PADS-开发指南】

馒头破戒大师

sinat_23896491的博客 3225

MaxEnt物种分布预测中的常见误区与优化技巧:如何提高模型准确率

本文深入探讨了MaxEnt物种分布预测模型从基础应用到精准预测的进阶实践。针对模型准确率提升,文章系统分析了环境变量筛选、模型参数调优、结果批判性解读等核心环节的常见误区,并提供了基于生态位模型原理的深度优化技巧,帮助研究者产出更可靠、可解释的预测结果。

weixin_29219539的博客 595

PAT_(模拟)A1042 A1046 A1065 A1002 A1009

目录 1002A+B for Polynomials(25分) 1009Product of Polynomials(25分) 1042Shuffling Machine(20分) 1046Shortest Distance(20分) 1065A+B and C (64bit)(20分) 1002A+B for Polynomials(25分) 多...

weixin_43107805的博客 405

DCMM评估报告模板样例

这篇DCMM评估报告对某数据管理公司2020年的数据管理能力进行了全面分析。报告显示,该公司在数据战略方面取得初步进展,但在数据治理和数据架构方面仍存在明显不足,包括缺乏有效治理流程、数据质量监控不足,以及数据标准化和转换灵活性不足等问题。评估报告提出了针对性改进建议,包括完善数据战略、建立治理流程、加强质量监控和提升数据转换灵活性等,为提升数据管理成熟度提供了重要指导。

cdfunlove的博客 166

K - Minimize the string

You are given n strings s1, s2, ..., sn. Each of these strings consists only of letters 'a' and 'b', and the length of each string can be at most 2. In other words, the only allowed strings are "a", "...

chen_zan_yu_的博客 560

【ARM CoreLink 系列 7 -- TZC-400控制器简介】

为了确保内存能够正确识别总线的信号控制位,新增一个TrustZone地址空间控制器(TrustZone Address Space Controller,TZASC)组件来实现对内存地址的安全扩展,将内存区域划分为安全内存区域和非安全内存区域,安全世界可以访问安全内存和非安全内存,而普通世界只能访问非安全内存,如下图所示:图 1-1内存区域的划分是在系统启动时通过配置 TZASC 组件(TZC-400/TZC-380)来实现的。TZC-400由和使能情况;安全访问权限;Base地址;

CodingCos的博客 1634

药物对接仿真软件:HADDOCK_(3).分子对接基本原理

分子对接(Molecular Docking)是计算化学和结构生物学中的一种重要技术,用于预测小分子(如药物分子)与大分子(如蛋白质)之间的相互作用模式和结合亲和力。这一技术在药物设计和开发中具有广泛的应用,尤其是在寻找和优化潜在的药物候选物方面。本节将详细介绍分子对接的基本原理,包括其理论基础、计算方法和应用。

kkchenjj的博客 1170

数据结构与算法 贪心法

1-2 Let S be the set of activities in Activity Selection Problem. Then there must be some maximum-size subset of mutually compatible activities of S that includes the earliest finish activity a m T 1-3 令S为活动选择问题(Activity Selection Problem)中所有活

m0_51424656的博客 1013

深度学习工具包 DeepLearningToolbox

深度学习工具包Deprecation notice.-----This toolbox is outdated and no longer maintained.There are much better tools available for deep learning than this toolbox, e.g. [Theano](http://deeplearning.net/software/theano/), [torch](http://torch.ch/) or [tensorflow](http://www.tensorflow.org/)I would suggest you use one of the tools mentioned above rather than use this toolbox.Best, Rasmus.DeepLearnToolbox================A Matlab toolbox for Deep Learning.Deep Learning is a new subfield of machine learning that focuses on learning deep hierarchical models of data.It is inspired by the human brain's apparent deep (layered, hierarchical) architecture.A good overview of the theory of Deep Learning theory is[Learning Deep Architectures for AI](http://www.iro.umontreal.ca/~bengioy/papers/ftml_book.pdf)For a more informal introduction, see the following videos by Geoffrey Hinton and Andrew Ng.* [The Next Generation of Neural Networks](http://www.youtube.com/watch?v=AyzOUbkUf3M) (Hinton, 2007)* [Recent Developments in Deep Learning](http://www.youtube.com/watch?v=VdIURAu1-aU) (Hinton, 2010)* [Unsupervised Feature Learning and Deep Learning](http://www.youtube.com/watch?v=ZmNOAtZIgIk) (Ng, 2011)If you use this toolbox in your research please cite [Prediction as a candidate for learning deep hierarchical models of data](http://www2.imm.dtu.dk/pubdb/views/publication_details.php?id=6284)```@MASTERSTHESIS\{IMM2012-06284, author = "R. B. Palm", title = "Prediction as a candidate for learning deep hierarchical models of data", year = "2012",}```Contact: rasmusbergpalm at gmail dot comDirectories included in the toolbox-----------------------------------`NN/` - A library for Feedforward Backpropagation Neural Networks`CNN/` - A library for Convolutional Neural Networks`DBN/` - A library for Deep Belief Networks`SAE/` - A library for Stacked Auto-Encoders`CAE/` - A library for Convolutional Auto-Encoders`util/` - Utility functions used by the libraries`data/` - Data used by the examples`tests/` - unit tests to verify toolbox is workingFor references on each library check REFS.mdSetup-----1. Download.2. addpath(genpath('DeepLearnToolbox'));Example: Deep Belief Network---------------------```matlabfunction test_example_DBNload mnist_uint8;train_x = double(train_x) / 255;test_x = double(test_x) / 255;train_y = double(train_y);test_y = double(test_y);%% ex1 train a 100 hidden unit RBM and visualize its weightsrand('state',0)dbn.sizes = [100];opts.numepochs = 1;opts.batchsize = 100;opts.momentum = 0;opts.alpha = 1;dbn = dbnsetup(dbn, train_x, opts);dbn = dbntrain(dbn, train_x, opts);figure; visualize(dbn.rbm{1}.W'); % Visualize the RBM weights%% ex2 train a 100-100 hidden unit DBN and use its weights to initialize a NNrand('state',0)%train dbndbn.sizes = [100 100];opts.numepochs = 1;opts.batchsize = 100;opts.momentum = 0;opts.alpha = 1;dbn = dbnsetup(dbn, train_x, opts);dbn = dbntrain(dbn, train_x, opts);%unfold dbn to nnnn = dbnunfoldtonn(dbn, 10);nn.activation_function = 'sigm';%train nnopts.numepochs = 1;opts.batchsize = 100;nn = nntrain(nn, train_x, train_y, opts);[er, bad] = nntest(nn, test_x, test_y);assert(er < 0.10, 'Too big error');```Example: Stacked Auto-Encoders---------------------```matlabfunction test_example_SAEload mnist_uint8;train_x = double(train_x)/255;test_x = double(test_x)/255;train_y = double(train_y);test_y = double(test_y);%% ex1 train a 100 hidden unit SDAE and use it to initialize a FFNN% Setup and train a stacked denoising autoencoder (SDAE)rand('state',0)sae = saesetup([784 100]);sae.ae{1}.activation_function = 'sigm';sae.ae{1}.learningRate = 1;sae.ae{1}.inputZeroMaskedFraction = 0.5;opts.numepochs = 1;opts.batchsize = 100;sae = saetrain(sae, train_x, opts);visualize(sae.ae{1}.W{1}(:,2:end)')% Use the SDAE to initialize a FFNNnn = nnsetup([784 100 10]);nn.activation_function = 'sigm';nn.learningRate = 1;nn.W{1} = sae.ae{1}.W{1};% Train the FFNNopts.numepochs = 1;opts.batchsize = 100;nn = nntrain(nn, train_x, train_y, opts);[er, bad] = nntest(nn, test_x, test_y);assert(er < 0.16, 'Too big error');```Example: Convolutional Neural Nets---------------------```matlabfunction test_example_CNNload mnist_uint8;train_x = double(reshape(train_x',28,28,60000))/255;test_x = double(reshape(test_x',28,28,10000))/255;train_y = double(train_y');test_y = double(test_y');%% ex1 Train a 6c-2s-12c-2s Convolutional neural network %will run 1 epoch in about 200 second and get around 11% error. %With 100 epochs you'll get around 1.2% errorrand('state',0)cnn.layers = { struct('type', 'i') %input layer struct('type', 'c', 'outputmaps', 6, 'kernelsize', 5) %convolution layer struct('type', 's', 'scale', 2) %sub sampling layer struct('type', 'c', 'outputmaps', 12, 'kernelsize', 5) %convolution layer struct('type', 's', 'scale', 2) %subsampling layer};cnn = cnnsetup(cnn, train_x, train_y);opts.alpha = 1;opts.batchsize = 50;opts.numepochs = 1;cnn = cnntrain(cnn, train_x, train_y, opts);[er, bad] = cnntest(cnn, test_x, test_y);%plot mean squared errorfigure; plot(cnn.rL);assert(er<0.12, 'Too big error');```Example: Neural Networks---------------------```matlabfunction test_example_NNload mnist_uint8;train_x = double(train_x) / 255;test_x = double(test_x) / 255;train_y = double(train_y);test_y = double(test_y);% normalize[train_x, mu, sigma] = zscore(train_x);test_x = normalize(test_x, mu, sigma);%% ex1 vanilla neural netrand('state',0)nn = nnsetup([784 100 10]);opts.numepochs = 1; % Number of full sweeps through dataopts.batchsize = 100; % Take a mean gradient step over this many samples[nn, L] = nntrain(nn, train_x, train_y, opts);[er, bad] = nntest(nn, test_x, test_y);assert(er < 0.08, 'Too big error');%% ex2 neural net with L2 weight decayrand('state',0)nn = nnsetup([784 100 10]);nn.weightPenaltyL2 = 1e-4; % L2 weight decayopts.numepochs = 1; % Number of full sweeps through dataopts.batchsize = 100; % Take a mean gradient step over this many samplesnn = nntrain(nn, train_x, train_y, opts);[er, bad] = nntest(nn, test_x, test_y);assert(er < 0.1, 'Too big error');%% ex3 neural net with dropoutrand('state',0)nn = nnsetup([784 100 10]);nn.dropoutFraction = 0.5; % Dropout fraction opts.numepochs = 1; % Number of full sweeps through dataopts.batchsize = 100; % Take a mean gradient step over this many samplesnn = nntrain(nn, train_x, train_y, opts);[er, bad] = nntest(nn, test_x, test_y);assert(er < 0.1, 'Too big error');%% ex4 neural net with sigmoid activation functionrand('state',0)nn = nnsetup([784 100 10]);nn.activation_function = 'sigm'; % Sigmoid activation functionnn.learningRate = 1; % Sigm require a lower learning rateopts.numepochs = 1; % Number of full sweeps through dataopts.batchsize = 100; % Take a mean gradient step over this many samplesnn = nntrain(nn, train_x, train_y, opts);[er, bad] = nntest(nn, test_x, test_y);assert(er < 0.1, 'Too big error');%% ex5 plotting functionalityrand('state',0)nn = nnsetup([784 20 10]);opts.numepochs = 5; % Number of full sweeps through datann.output = 'softmax'; % use softmax outputopts.batchsize = 1000; % Take a mean gradient step over this many samplesopts.plot = 1; % enable plottingnn = nntrain(nn, train_x, train_y, opts);[er, bad] = nntest(nn, test_x, test_y);assert(er < 0.1, 'Too big error');%% ex6 neural net with sigmoid activation and plotting of validation and training error% split training data into training and validation datavx = train_x(1:10000,:);tx = train_x(10001:end,:);vy = train_y(1:10000,:);ty = train_y(10001:end,:);rand('state',0)nn = nnsetup([784 20 10]); nn.output = 'softmax'; % use softmax outputopts.numepochs = 5; % Number of full sweeps through dataopts.batchsize = 1000; % Take a mean gradient step over this many samplesopts.plot = 1; % enable plottingnn = nntrain(nn, tx, ty, opts, vx, vy); % nntrain takes validation set as last two arguments (optionally)[er, bad] = nntest(nn, test_x, test_y);assert(er < 0.1, 'Too big error');```[![Bitdeli Badge](https://d2weczhvl823v0.cloudfront.net/rasmusbergpalm/deeplearntoolbox/trend.png)](https://bitdeli.com/free "Bitdeli Badge")

PAT甲级 1002 A+B for Polynomials

PAT甲级 1002 A+B for Polynomials This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and e...

旺崽的博客 2889

锂电池充电器电路设计 里面有电路

锂电池充电器电路设计 里面有电路 3.7V升压到5V电路设计。

IMSL CNL 7.0.0 (x86-64)Crack

IMSL CNL 7.0.0 (x86-64)Crack intel的算法库破解文件,这是C++版本的破解文件

1002 A+B for Polynomials (25分)

PAT (Advanced Level) Practice 题目链接. 编程题 1002 A+B for Polynomials (25分) 参考自《算法笔记》 This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file con...

陈三千的博客 286

IEM模型,地表粗糙度模拟

利用微波反演土壤水分时候,利用IEM模型可以实现对随机地表的模拟

PAT甲级 - 1002 A+B for Polynomials (25 分)

题目链接:(PAT甲级)1002 A+B for Polynomials (25 分) This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupie...

515

PAT甲级1002 A+B for Polynomials (25分)

PAT甲级1002 A+B for Polynomials (25分) 题目: 解题思路:这是一题多项式相加的问题,主要考察对于输出格式的理解与应用,以及数组的上边界,先将数据读入,因为是两行而且行间有空格,但空格不必读入,故使用scanf来读入,读入double类型时用%lf,而输出时用%.1f,用来保留一位小数。看清楚,不是lf而是1f(哈哈哈,检查了半天没检查出来,巨弱一枚),最后输出时候...

weixin_43795683的博客 465

PAT 甲级 1002 A+B for Polynomials (25 分)

题目:PAT 甲级 1002 A+B for Polynomials (25 分) 经验总结: 系数之和有三种情况:正数、0、负数。 此题可用map解决,使用键(key)来表示项幂,值(value)来表示其系数。 特别要注意系数之和为0的情况,如果使用map解决的话就要特别注意,因为系数之和为0的项是不输出的,所以map中系数为0的项得删除(因为之后还有统计项数,所以最好删除系数为0的项,而...

努力努力再努力 203

PAT甲级1002题A+B for Polynomials

PAT甲级1002题A+B for Polynomials 原题传送链接 题目描述: 1002A+B for Polynomials(25分) This time, you are supposed to findA+BwhereAandBare two polynomials. Input Specification: Each input file cont...

theStrongestPit的博客 688

PAT 甲级题目讲解:1002《A+B for Polynomials》

本文是 PAT 甲级 1002 题《A+B for Polynomials》的详细题解,介绍了多项式加法的实现方法:使用数组以指数为下标、累加系数,再统计非零项并按降幂输出。文章涵盖题目要求、样例分析、解题思路、完整代码、常见错误提醒及复杂度分析,并提供思维拓展,帮助读者掌握稀疏多项式合并的典型处理技巧。

qq_35624947的博客 851

(PTA记录)1002 A+B for Polynomials (25分)

(PTA记录)1002 A+B for Polynomials (25分) 题目内容: This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a poly

qq_38437955的博客 325

PAT练习题(甲级) 1002 A+B for Polynomials

PAT练习题 1002 A+B for Polynomials This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and ...

CoderHqf的博客 9437

PAT1002. A+B for Polynomials

原题链接 PAT1002. A+B for Polynomials 解题思路 注意合并之后系数为0的项,就无需再输出的。这个点注意了就好。 代码 #include <bits/stdc++.h> #include <iomanip> using namespace std; double a[10010]; //0-1000 int main(){ //2 1 2.4 0...

我是没有梦想的小白 233

[PAT 甲级] 1002 A+B for Polynomials (25 分)

1002 A+B for Polynomials (25 分) 原题链接 This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines,...

cp0328的博客 3396

PAT 1002 A+B for Polynomials

PAT 1002 A+B for Polynomials (25分) This time, you are supposed to find A+B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, a...

weixin_43661154的博客 241

编程小白的PAT试题笔记_A1002 A+B for Polynomials

#TOC[&amp;lt;编程小白的PAT试题笔记&amp;gt;A1002 A+B for Polynomials]

Ker's Woooorld 413
上一篇: 1001 A+B Format (20分)(一个字短!)
下一篇: 1003 Emergency (25分)(一个字短!)
大了七八个
博客等级 码龄8年 2粉丝 30原创
评论
成就一亿技术人!
拼手气红包6.0元
还能输入1000个字符
 
 条评论被折叠 查看
添加红包

请填写红包祝福语或标题

个

红包个数最小为10个

元

红包金额最低5元

当前余额3.43元 前往充值 >
需支付:10.00元
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付元
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值